Depends on the situation. You usually have to multiply numerator and denominator by some number or expression. Examples: 1 / square root of 2 Here, you have to multiply numerator and denominator by the square root of 2. 1 / (square root of 2 + square root of 3) Here, you have to multiply numerator and denominator by (square root of 2 - square root of 3).
Only if the square root of the numerator and the square root of the denominator are both rational numbers.
its false apex :)
That is called "rationalizing the denominator". It consists of multiplying the numerator and the denominator by specific terms, which include square roots. Examples:* If the denominator is root(2) (that is, the square root of 2), multiply numerator and denominator by root(2). * If the denominator is root(2) + root(3), multiply numerator and denominator by root(2) - root(3).
The idea is to get rid of the square root in the denominator. For this purpose, you must multiply numerator and denominator by the square root of 6 in this case.
It is called rationalizing the denominator, and it is done by multiplying numerator and denominator by appropriate numbers. Note that if you do that, you will usually end up with radicals in the numerator. Examples: 1 / (square root of 2): Multiply numerator and denominator by the square root of 2. 1 / (square root of 2 + square root of 3): Multiply numerator and denominator by (square root of 2 - square root of 3).
Depends on the situation. You usually have to multiply numerator and denominator by some number or expression. Examples: 1 / square root of 2 Here, you have to multiply numerator and denominator by the square root of 2. 1 / (square root of 2 + square root of 3) Here, you have to multiply numerator and denominator by (square root of 2 - square root of 3).
Of course you can. You can have a square root anywhere it needs to be to get the correct answer!
find the square root of the numerator and the square root of the denominator
Only if the square root of the numerator and the square root of the denominator are both rational numbers.
its false apex :)
A square root of a fraction applies to both the numerator and denominator, so it would be 6/8 or 3/4.
That is called "rationalizing the denominator". It consists of multiplying the numerator and the denominator by specific terms, which include square roots. Examples:* If the denominator is root(2) (that is, the square root of 2), multiply numerator and denominator by root(2). * If the denominator is root(2) + root(3), multiply numerator and denominator by root(2) - root(3).
The idea is to get rid of the square root in the denominator. For this purpose, you must multiply numerator and denominator by the square root of 6 in this case.
Yes. The square root of a fraction is the square root of the numerator over the square root of the denominator. First simplify the fraction (making mixed numbers into improper fractions). Now consider the numerator and denominator separately as whole numbers. Only perfect squares (the squares of whole numbers) have rational square roots. If either, or both, of the numerator and denominator is not a perfect square, the square root of the fraction will be irrational √(11/6) = (√11)/(√6). Neither 11 nor 6 is a perfect square, thus √(11/6) is irrational.
Well, honey, to find the square root of 625 over 36, you first find the square root of the numerator (625) which is 25, and the square root of the denominator (36) which is 6. So, the square root of 625 over 36 is 25 over 6. Math doesn't have to be as complicated as your ex's drama, darling.
This is related to the technique used to eliminate square roots from the denominator. If, for example, the denominator is 4 + root(3), you multiply both numerator and denominator by 4 - root(3). In this case, "4 - root(3)" is said to be the "conjugate" of "4 + root(3)". When doing this, there will be no more square roots in the denominator - but of course, you'll instead have a square root in the numerator.