it would weigh the same because the mortor comes from earth
no
This would be known as the Equator
If you assume thatequatriol = equatorial raduis = radius then the equatorial radius is the radius of the spheroid measured at its equator. It would be = length of the equator/(2*pi)
The earth's equator is approximately 40,075 kilometres. There is no exact value because, amongst other things, the equator is not static: it moves with shifts in the axis of the earth's rotation.However, using calculus, it is possible to show that the length of the string would need to be 2*pi inches = 6.3 inches greater than the length of the equator measured in inches. Given the variability in measuring the earth's equator, that difference will not be identifiable.The earth's equator is approximately 40,075 kilometres. There is no exact value because, amongst other things, the equator is not static: it moves with shifts in the axis of the earth's rotation.However, using calculus, it is possible to show that the length of the string would need to be 2*pi inches = 6.3 inches greater than the length of the equator measured in inches. Given the variability in measuring the earth's equator, that difference will not be identifiable.The earth's equator is approximately 40,075 kilometres. There is no exact value because, amongst other things, the equator is not static: it moves with shifts in the axis of the earth's rotation.However, using calculus, it is possible to show that the length of the string would need to be 2*pi inches = 6.3 inches greater than the length of the equator measured in inches. Given the variability in measuring the earth's equator, that difference will not be identifiable.The earth's equator is approximately 40,075 kilometres. There is no exact value because, amongst other things, the equator is not static: it moves with shifts in the axis of the earth's rotation.However, using calculus, it is possible to show that the length of the string would need to be 2*pi inches = 6.3 inches greater than the length of the equator measured in inches. Given the variability in measuring the earth's equator, that difference will not be identifiable.
Mass would be the same at the equator and at the pole - except for an insignificant change due to the General Theory of Relativity. Weight would be more at the pole.
To calculate weight at the equator and pole, you need to consider the effect of gravity. At the equator, the centrifugal force due to the Earth's rotation slightly reduces weight compared to the pole. The weight at the pole is higher because the centrifugal force is lower there. However, the difference in weight between the pole and equator is very small and often negligible for everyday purposes.
In that case, your weight remains absolutely constant and does not budge one iota.
The weight of an object is less at the equator compared to the poles due to the centripetal force produced by the Earth's rotation. At the equator, this force partially counteracts the force of gravity, effectively reducing the object's weight. This difference in weight is more noticeable for objects with larger mass.
The weight of an object changes when it is moved from the equator to the poles due to the variation in gravitational force caused by the Earth's rotation. The force of gravity is slightly stronger at the poles compared to the equator, leading to a small change in weight.
The weight of an object would not change when taken from Delhi to the pole. Weight is the force of gravity acting on an object, and this force remains constant regardless of location. The object's mass would remain the same, but its weight may be perceived differently due to variations in gravity strength at different locations.
Yes, there would be a difference between the mass and weight measured at the North Pole and the Equator. Mass remains the same regardless of location, while weight would be slightly higher at the North Pole due to the stronger gravitational pull compared to the Equator where it is slightly weaker.
Your weight may decrease slightly when moving from the poles to the equator due to the Earth's rotation causing a centrifugal force that counteracts gravity slightly. This effect is small and would be more noticeable at the equator due to the larger radius of Earth at that point compared to the poles.
That would depend on exactly where on the the equator you are. If you are on the equator by Brazil then you would have to steer south. If you are on the equator nea PNG the you have to steer east.
That would depend on exactly where on the the equator you are. If you are on the equator by Brazil then you would have to steer south. If you are on the equator nea PNG the you have to steer east.
If the Earth were to rotate faster, the object's weight would decrease slightly due to a change in centrifugal force. This effect would be more noticeable at the equator compared to the poles. However, the change in weight would be minimal for most everyday objects.
you would be closer to the equator!!