Q: What would your weight be at the equator?

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it would weigh the same because the mortor comes from earth

no

This would be known as the Equator

If you assume thatequatriol = equatorial raduis = radius then the equatorial radius is the radius of the spheroid measured at its equator. It would be = length of the equator/(2*pi)

The earth's equator is approximately 40,075 kilometres. There is no exact value because, amongst other things, the equator is not static: it moves with shifts in the axis of the earth's rotation.However, using calculus, it is possible to show that the length of the string would need to be 2*pi inches = 6.3 inches greater than the length of the equator measured in inches. Given the variability in measuring the earth's equator, that difference will not be identifiable.The earth's equator is approximately 40,075 kilometres. There is no exact value because, amongst other things, the equator is not static: it moves with shifts in the axis of the earth's rotation.However, using calculus, it is possible to show that the length of the string would need to be 2*pi inches = 6.3 inches greater than the length of the equator measured in inches. Given the variability in measuring the earth's equator, that difference will not be identifiable.The earth's equator is approximately 40,075 kilometres. There is no exact value because, amongst other things, the equator is not static: it moves with shifts in the axis of the earth's rotation.However, using calculus, it is possible to show that the length of the string would need to be 2*pi inches = 6.3 inches greater than the length of the equator measured in inches. Given the variability in measuring the earth's equator, that difference will not be identifiable.The earth's equator is approximately 40,075 kilometres. There is no exact value because, amongst other things, the equator is not static: it moves with shifts in the axis of the earth's rotation.However, using calculus, it is possible to show that the length of the string would need to be 2*pi inches = 6.3 inches greater than the length of the equator measured in inches. Given the variability in measuring the earth's equator, that difference will not be identifiable.

Related questions

In that case, your weight remains absolutely constant and does not budge one iota.

equator

gravity

the Equator, but not by much.

By the equator.

No, they would not. The sun would reach the overhead point at the equator but would always be at the horizon at the poles.

Neither. It is North of the Equator. If you mean the Prime Meridian, then the answer would be West.

the equator? Yes, the equator in the Indian Ocean.

Capricorn

Madison is slightly closer to the equator than the North Pole.

You may want to rephrase the question. The kilometer is a unit of length or distance, not weight. However, gravitational acceleration at Mars equator is equal to about 3.71 m/s2. Since g on earth is about 9.8m/s2 weight on Mars is about 1/2.64 times earth weight.

It all depends if you are coming from Texas it would be South.Tropic of Cancer is above the equator so anything above the equator in the United States will be traveling down which is South.That is even for the equator.. Hopes this help