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What z score represents the 90 th percentile?
z = 1.281551
A z-score of -1.0 represents a percentile rank of roughly?
between 15 and 20.
What is the formula to convert a z score into a percentile rank?
You need to look up z-score tables.
What percentile rank would represent a person with a z score of 3?
The top percentile (> 99.86%)
What is the z score that corresponds to P78?
The z-score that corresponds to P78 (the 78th percentile) can be found using a standard normal distribution table or calculator. It indicates that 78% of the data falls below this z-score. For a standard normal distribution, the z-score for P78 is approximately 0.77. This means that a value at the 78th percentile is about 0.77 standard deviations above the mean.
What z score represents the 90 th percentile?
z = 1.281551
What z-score represents the 99th percentile?
2.326
What z score represents the 80th percentile?
To find what z-score represents the 80th percentile, simply solve for 0.8 = F(z), where F(x) is the standard normal cumulative distribution function. Solving gives us: z = 0.842
What is the z score representing the 10th percentile of the standard normal distribution?
Right around -1.28
A z-score of -1.0 represents a percentile rank of roughly?
between 15 and 20.
What is the nearest percentile associated with the z-score 0.68?
75th percentile.
What is the z score that corresponds to the 5th percentile?
z = -1.644853 (approx).
What is the formula to convert a z score into a percentile rank?
You need to look up z-score tables.
What percentile rank would represent a person with a z score of 3?
The top percentile (> 99.86%)
Find z score for normal distribution for 70 percentile?
z = 0.5244, approx.
What is the percentile if a z- score is 0.62?
To determine the percentile of a z-score, you would look up the z-score in a standard normal distribution table. A z-score of 0.62 corresponds to a percentile of approximately 73.8%. This means that 73.8% of the data in a standard normal distribution falls below a z-score of 0.62.
Find z score for normal distribution for 60th percentile?
it doesn't exist.
