2 8/21 i believe
2 can go into 47 a total of 23 times with a remainder of 1. This is because 2 multiplied by 23 equals 46, which is the largest multiple of 2 that is less than 47. Therefore, you can express it as 47 = 2 × 23 + 1.
To find how many times 2 fits into 47, you can divide 47 by 2. Doing the calculation, 47 divided by 2 equals 23 with a remainder of 1. Therefore, there are 23 complete 2s in 47.
The GCF is 1.
23 and 1
It is: 1 times 47 = 47 which is a prime number
2 can go into 47 a total of 23 times with a remainder of 1. This is because 2 multiplied by 23 equals 46, which is the largest multiple of 2 that is less than 47. Therefore, you can express it as 47 = 2 × 23 + 1.
23 with remainder 1.
2 and remainder 1.
To find how many times 2 fits into 47, you can divide 47 by 2. Doing the calculation, 47 divided by 2 equals 23 with a remainder of 1. Therefore, there are 23 complete 2s in 47.
23, remainder 1
The GCF is 1.
23 and 1
It is: 1 times 47 = 47 which is a prime number
1 × 47 = 47
47
47 is already prime. The factors are 1 and 47.
47 x 1