7 yd 1 ft - 5 yd 2 ft = 22 ft - 17 ft = 5 ft = 1 yd 2 ft.
9 yd 2 ft. Incidentally, 2 yd 4 ft is a strange way of representing a distance of 3 yd 1 ft.
59 yd and 1 ft
there are 3 ft in 1 yd. therefore, there are 9 ft in 3 yd
2 yd 2 ft
7 yd 1 ft - 5 yd 2 ft = 22 ft - 17 ft = 5 ft = 1 yd 2 ft.
1 yd- 1 ft = 0
3 ft = 1 yd 1 sq ft = 1 ft × 1 ft = (1 ÷ 3) yd × (1 ÷ 3) yd = 1/9 sq yd → 100 sq ft = 100 × 1/9 sq yd = 11 1/9 sq yd ≈ 11.1 sq yd
1 yd = 3 ft 1 sq yd = 1 yd x 1 yd = 3 ft x 3 ft = 9 sq ft ⇒ 1 sq ft = 1/9 sq yd ≈ 0.11 sq yd
1 yd = 3 ft 1 yd * 1 yd = 1 yd2 = 3 ft * 3 ft = 9 ft2
9 yd 2 ft. Incidentally, 2 yd 4 ft is a strange way of representing a distance of 3 yd 1 ft.
59 yd and 1 ft
12 yd 2 ft- 9 yd 1 ft--------------3 yd 1 ft
Assuming you mean the colloquial (builder's) yard for cubic yard: 36 in = 1 yd 3 ft = 1 yd ⇒ 3 ft x 3 ft = 1 yd x 1 yd ⇒ 9 sq ft = 1 sq yd ⇒ 4500 sq ft x 1 in = (4500 ÷ 9) sq yd x (1 ÷ 36) yd = 138/9 cu yd ≈ 13.89 cu yd
there are 3 ft in 1 yd. therefore, there are 9 ft in 3 yd
2 yd 2 ft
64.8 square feet 36 in = 1 yd 1 cu yd = 1 sq yd x 1 yd 1 yd = 3 ft 1 sq yd = 1 yd x 1 yd = 3 ft x 3 ft = 9 sq ft volume = area x thickness ⇒ area = volume ÷ thickness = 1 sq yd x 1 yd ÷ 5 in = 1 sq yd x 1 yd ÷ (5 ÷ 36) yd = 7.2 sq yd = 7.2 x 9 sq ft = 64.8 sq ft