A regular decagon; A 20-gon with 2 lots of 10 congruent sides and angles in an alternating pattern; A 30-gon with 3 lots of 10 congruent sides and angles in an 1-2-3-1-2-3 pattern; A 40-gon with 4 lots of 10 congruent sides and angles in an 1-2-3-4-1-2-3-4 pattern; etc.
The full series should be: {1, 3, 6, 10, 12, 12, 10, 6, 3, 1} It is nothing more than a series that increases in a certain way & then decreases in the exact opposite way. You can see this by using subtraction as follows: 3-1 = 2 6-3 = 3 10-6 = 4 12-10 = 2 12-12 = 0 12-10 = 2 10-6 = 4 6-3 = 3 3-1 = 2 Notes: - the series pattern increases to 12 in this way: 2, 3, 4, 2 - the series pattern then decreases from 12 in the exact opposite way: 2, 4, 3, 2 - if graphed with time as the x-coordinate & each number as the y-coordinates, the full series would resemble a curve that looks similar to a hill with a flat top.
The answer for the number that follows the sequence 4-6-3-7-9-6-10 is 12. The pattern is +2,-3,+4,+2,-3,+4,.....,+2,-3,+4,...
10.1(+2) 3 (+3) 6 (+4) 10
12, 10 and 15 the are alternatively increased by 2 and 3
you add all the numbers before it 2 3 2+3=5 2+3+5=10 . . .
kothari commission
It is 1 9 2 8 3 7 4 6 5 5 : 1 + 9 = 10 2 + 8 = 10 3 + ? = 10 ----> 3 + 7 = 10
Subtract 2, then multiply by 3, -2, *3, etc
A regular decagon; A 20-gon with 2 lots of 10 congruent sides and angles in an alternating pattern; A 30-gon with 3 lots of 10 congruent sides and angles in an 1-2-3-1-2-3 pattern; A 40-gon with 4 lots of 10 congruent sides and angles in an 1-2-3-4-1-2-3-4 pattern; etc.
Seperate like this: 2 1 2 3 2 6 2 10 2 ? then categorize them two by two: 2 1 2 3 2 6 2 10 2 ? now this is the question : 1 3 6 10 ? and the answer is 15" 1 + 2 = 3 ---> + 3 = 6 ----> + 4 = 10 ----> + 5 =15
t(n) = 3(n-1) + 1, for n = 1, 2, 3, etc
divide by 2 and add 1
it goes by odd numbers, 2 + 3= 5, 5+5=10, 10 + 7=17 the rest of the pattern is 26, 37, and 50
7 is the next number in the pattern
1 10 2 9 3 8 4 7 5 6 6 5 7 4 8 3 9 2 10 1
7