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Q: When Joanne checked her work by substituting the value of the variable back into the equation she got an answer of 12.34 equals 12.33 Explain why Joanne could have gotten the answer correct even tho?

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You need to be sure the variable denominator does not become zero, where the equation would not be defined.

The idea is to have some variable as a counter, which starts at 1, is incremented by 1 in each round, and checked to see whether it is more than the desired number of repetitions.

1 Identify the problem 2 Simplify the problem whenever possible 3 Work out the problem 4 Problem solved when checked out satisfactory

The brute force way would be to iterate through all the integers smaller than the sought number and check the number is divisible by each of them. However this algorithm is extremely inefficient, but improving upon the simple idea, we can come up with an algorithm: #include <stdio.h> #include <stdlib.h> #include <math.h> /* * */ int main(int argc, char** argv) { int checked = 72; //put your number that you want to check int temp = 2; //the temporary variable to check against char isPrime = 1; //intially assume it is prime if (checked != 1 checked != 2) { while (temp <= sqrt((double) checked)) { //only have to check up to the square root of checked if (checked % temp 0) { temp += 1; //only have to check odd numbers } else { temp += 2; } } } if (isPrime) { printf("Checked is prime!\n"); } else { printf("Checked is not prime!\n"); } return (EXIT_SUCCESS); } or a better edited version here: http://img689.imageshack.us/img689/8164/primecodec.png

Multiply first equation by 3 and second equation by 5:30x + 27y = 12, -30x + 20y = -25; add these two:47y = -13, making y = -13/47 and x = -61/94I have checked these values against the original equations and they satisfy both. Weird solution tho'!

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You need to be sure the variable denominator does not become zero, where the equation would not be defined.

By replacing a number for the variable.

One variable will be included, then the effect checked, then the next variable inserted, et al

An experiment usually involves a set of steps involving one variable. This is what is being tested. A control involves the same steps without the one variable. The results are checked against each other to see if the variable had any effect.

An experiment usually involves a set of steps involving one variable. This is what is being tested. A control involves the same steps without the one variable. The results are checked against each other to see if the variable had any effect.

An experiment usually involves a set of steps involving one variable. This is what is being tested. A control involves the same steps without the one variable. The results are checked against each other to see if the variable had any effect.

Baby position keeps on changing while doing scanning is called "Variable presentation"..I have checked this with doctor and she said it is not a problem in 5th month as sufficient time is there for the baby to change its position for normal delivery.. K.Veeramani from India..

It is special variable that has a lit of directories there all our applications are located. In other to find out this PATH variable in UNIX type operating system use env command and look for PATH variable in ENVIRONMENT variables list or use bash line: echo $PATH this will return only $PATH variable.For example my PATH variable is:/Users/david/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/usr/X11/binWhen you will try to launch a program by writing it's name in console all those directories you see in PATH variable will be checked for that application.

Suppose you have checkbox in HTML from and and you are calling that checkbox by name in php , In that case in you don't check and hit submit , You will get Undefined parameter 'name_of _checkbox' As Error.

It's called a diphthong literally, checked out a dictionary it will explain it a little more