To find the speed of the combined masses after the collision, we can use the conservation of momentum. The initial momentum of the system is given by the momentum of spaceship 2, since spaceship 1 is at rest: ( p_{initial} = m_2 \cdot v_2 = 200 , \text{kg} \cdot 6 , \text{m/s} = 1200 , \text{kg m/s} ). After the collision, the two spaceships stick together, so their combined mass is ( 200 , \text{kg} + 200 , \text{kg} = 400 , \text{kg} ). Using the conservation of momentum, ( p_{initial} = p_{final} ), we have ( 1200 , \text{kg m/s} = 400 , \text{kg} \cdot v_{final} ), leading to ( v_{final} = 3 , \text{m/s} ).
2 m/s
2m/s
900kg-m/s
600kg-m/s apex miles
1,500 kg-m/s900 kg-m/s apex
3 m/s
2 m/s
3 m/s
2 m/sec in the direction of travel of Spaceship 2, assuming they are both in frictionless outer space.
2m/s
900kg-m/s
1800 kg-m/sec 600 kg x 3 meters/sec (in the direction spaceship 2 was headed). Since the first spaceship had all the initial momentum, only the velocity of the combined mass will change.
600kg-m/s apex miles
1,500 kg-m/s900 kg-m/s apex
The momentum of an object is given by the formula: momentum = mass x velocity. Therefore, the combined momentum of Spaceship 1 and Spaceship 2 after the collision would be the sum of their individual momentums. Since they have equal masses and are moving in the same direction, you can simply add their individual momentums to get the combined momentum.
momentum must be conserved momentum = mass*velocity initially momentum = 150*6 +150*0 = 900 kgms-1 final momentum = 300*combinedvelocity = 900 so the final velocity must be 3 ms-1
Multiply mass x velocity for each spaceship. Add the results.