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I think the simplest answer is any number divisible both by 2 and 3 (2x3=6), which is easy enough to figure out separately. All even numbers are divisible by 2, and all numbers divisible by 3 have their individual digits add up to a multiple of 3 (e.g. for 231, 2 + 3 + 1 = 6, and 6 is a multiple of 3, therefore 231 is also a multiple of 3).
In short, multiples of 6 are even numbers whose digits add up to a multiple of 3.
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Is the sum of a number that is a multiple of 3 and a number that is a multiple of 6 must be a multiple of 6?
yes exept for the numbers 3,9,15,21,27,33 etc
What number is a multiple of 4 and 6 as a factor?
The number 12 has 4 and 6 as factors so 12 is a multiple of 4 and 6.
How can you work out if a number is a multiple of 6?
Divide it by 6 and if 6 goes into it with no remainer then it must be a multiple of 6.
Why can a number which ends in 3 not be a multiple of 6?
A number that ends in 3 is an odd number, as it is not divisible by 2. For a number to be a multiple of 6, it must be divisible by both 2 and 3. Since a number ending in 3 is not divisible by 2, it cannot be a multiple of 6. In other words, any number ending in 3 will always have a remainder when divided by 6.
Why is 3 not a multiple of 6?
Three is not a multiple of 6 because you can't multiply 6 by a whole number and get the answer 3.
