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Q: When preparing a pr and c you must do what?
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If the Probability that a train arrives early is 0.09 probability late is 0.4 What is the probability it arrives on time?

The train can be either early, on time or late. The total probability must be 1. Thus: pr(early) + pr(on_time) + pr(late) = 1 0.09 + pr(on_time) + 0.4 = 1 => pr(on_time) = 1 - 0.4 - 0.09 = 0.51 Probability of being on time is 0.51


What is the describing of the complementary event and find its probability?

Suppose there is an event A and the probability of A happening is Pr(A). Then the complementary event is that A does not happen or that "not-A" happens: this is often denoted by A'.Then Pr(A') = 1 - Pr(A).Suppose there is an event A and the probability of A happening is Pr(A). Then the complementary event is that A does not happen or that "not-A" happens: this is often denoted by A'.Then Pr(A') = 1 - Pr(A).Suppose there is an event A and the probability of A happening is Pr(A). Then the complementary event is that A does not happen or that "not-A" happens: this is often denoted by A'.Then Pr(A') = 1 - Pr(A).Suppose there is an event A and the probability of A happening is Pr(A). Then the complementary event is that A does not happen or that "not-A" happens: this is often denoted by A'.Then Pr(A') = 1 - Pr(A).


What is the difference between the multiplication rule for independent versus dependent events?

Given two events, A and B, Pr(A and B) = Pr(A)*Pr(B) if A and B are independent and Pr(A and B) = Pr(A | B)*Pr(B) if they are not.


What composite number can be expressed as product of its factors?

None.A composite number c must have a prime factor psuch that 1 < p < c.Therefore the product of c's factors must be at least p*c which must be greater than c.


What is the probability of obtaining exactly three heads in four flips of a coin given that at least two are heads?

Pr(3H given &gt;= 2H) = Pr(3H and &gt;= 2H)/Pr(&gt;=2H) = Pr(3H)/Pr(&gt;=2H) = (1/4)/(11/16) = 4/11.

Related questions

When preparing a pr and c you must?

Flash reports are


Which pr focal group refers to soldiers dod civilians or contractors who must execute the isg and master the pr proficiencies?

The individual is the PR focal group.


Which pr focal groups refers to soldiers dod civilians or dod contractors who must execute the isg and master the pr proficiencies?

The individual is the PR focal group.


Which pr focal group refers to soldiers dod civilians dod contractors who must execute the 1sg and master the pr proficiencies?

The individual is the PR focal group.


Which PR focal group refers to soldiers DOD civilians or DOD contractors who must execute the 1sg and master the pr proficiencies?

The individual is the PR focal group.


What pr focal group refers to soldiers dod civilians or dod contractors who must execute the isg and master the PR proficiencies?

Idk.


Which pr focal group refers to soldiers dod civilians or dod contractors who must execute the isg and master the pr proficiencies?

The individual is the PR focal group.


When preparing a budget a person must consider their?

Income


What is the first thing a student must do when preparing a speech?

The first thing a student must do when preparing a speech is to identify their main message or thesis. This will guide the content and structure of their speech.


Prior to deployment individuals must complete?

PR standing Operation Procedures


If PQ 20 and QR 22 Then what does PR equal?

To find the length of PR, you can use the triangle inequality theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. In this case, PR must be less than the sum of PQ and QR, so PR &lt; 20 + 22 = 42. Therefore, PR could be any value less than 42.


If the Probability that a train arrives early is 0.09 probability late is 0.4 What is the probability it arrives on time?

The train can be either early, on time or late. The total probability must be 1. Thus: pr(early) + pr(on_time) + pr(late) = 1 0.09 + pr(on_time) + 0.4 = 1 =&gt; pr(on_time) = 1 - 0.4 - 0.09 = 0.51 Probability of being on time is 0.51