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what 4 turns can put a figure in its original positions
-- Ignore the decimal point; just multiply the two whole numbers. -- After the multiplication is done, put the decimal point back into the product. Put it in the right place so that the product has as many digits after the point as the original decimal had. If there aren't enough digits in the product to do that, add some zeros to the left end of it.
Put the values that you find (as the solution) back into one (or more) of the original equations and evaluate them. If they remain true then the solution checks out. If one equation does not contain all the variables involved in the system, you may have to repeat with another of the original equations.
Find the decimal point (if there is not one visible, it is "hiding" at the right hand end)Put it after the first non-zero digitCount the number of digits that it would need to move to get back to its original position (if this is to the left, make it negative); put this as the power of 10.Multiply the results of steps 2 and 3 together.Examples:1234:No decimal point so hiding after the 4: "1234."1.234to get decimal point back to original position it must move 3 digits right: 1031.234 x 10312.34:decimal point after the 21.234to get back to original position decimal point must move 1 digit right: 1011.234 x 1010.01234Decimal point after first zero1.234 (first non-zero digit is the 1 - the leading zeros are removed)to get back to original position decimal point must move 2 digits left: 10-21.234 x 10-2.
Get rid of the decimal by multiplying by 1000, and then put the thousand underneath to show the original is got back by dividing the bottom into the top: 10.025 is 10.025 x1000 / 1000 =10025/1000