Best Answer

If the two numbers are a and b, then:

√a √b = √(ab) = √36

→ ab = 36

So any two [positive] numbers whose product is 36 will be a solution, except the pair 1 and 36 as that has been specifically excluded; thus possible solutions are:

√4 x √9,

√2 x √18,

√(1/2) x √72,

√(1/4) x √144,

etc.

(The first one being the only solution where the square roots are whole numbers.)

Q: When the square root of one number is multiplied by the square root of a second number the product is the square root of 36 one of the numbers is not 1?

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