The initial velocity is 10 meters/sec and is thrown up against the gravitational pull of the earth. This means that the ball is experiencing a deceleration at the rate of 9.8 meters/sec/sec to bring its final velocity to zero.
v^2 - u^2 = 2gs where u is the initial velocity, v the final velocity, g is the acceleration or deceleration, and s is the distance traveled.
0^2 - 10^2 = 2 x (-9.8) x s
-100 = -19.6s
100 = 19.6s
s = 100/19.6 = 5.102 meters
Now v = u + gt where v is the final velocity, u is the initial velocty, g is the acceleration or deceleration, and t is the time. When the ball is thrown up with 10 meters/sec velocity it is acted upon by the deceleration of gravity until its velocity becomes zero.
So 0 = 10 - 9.8t
or 9.8t = 10
t = 1.020 seconds
The time for the ball to go up is 1.020 seconds and the same time is taken for the ball to come back for a total of 2.040 seconds.
This is a velocity question so u need to use uvaxt
The answer will depend on what "it" is, and on what its initial velocity is.
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
Depending on the value used for the acceleration due to gravity (9.8 ms-2 or 9.81 ms-2), the ball will go up to 11.48 m or 11.47 m (approx). It will be in the air for a total of 3.06 seconds.
If the person sat on the train their velocity relative to the ground would be 95kph. But he/she is goind 3kph to oppose this. So 95-3 = 92 kph to the north is velocity of person relative to the ground.
20.40
This is a velocity question so u need to use uvaxt
Assuming the acceleration due to gravity is -9.81 m/s^2, the time it takes for the baseball to hit the ground can be calculated using the formula: time = (final velocity - initial velocity) / acceleration. In this case, the final velocity will be 0 m/s when the baseball hits the ground. Calculating it would give you the time it takes for the baseball to hit the ground.
This result is because the wet ball carries more inertia to weight ratio before hitting the ground , it then compresses, loses some of the liquid weight, becomes lighter, and because of the initial inertial force, can therefore leave the ground at a greater velocity
Approx 9.8 metres per second^2, downwards.
The speed of the baseball when it hits the ground is 150 m/s, assuming no air resistance. This is because the initial velocity will decrease due to gravity until it reaches zero at the highest point, and then starts to increase again as it falls back down.
To find the initial velocity of the kick, you can use the equation for projectile motion. The maximum height reached by the football is related to the initial vertical velocity component. By using trigonometric functions, you can determine the initial vertical velocity component and then calculate the initial velocity of the kick.
The initial velocity of a projectile affects its range by determining how far the projectile will travel horizontally before hitting the ground. A higher initial velocity will result in a longer range because the projectile has more speed to overcome air resistance and travel further. Conversely, a lower initial velocity will result in a shorter range as the projectile doesn't travel as far before hitting the ground.
The object's initial distance above the ground The object's initial velocity
The velocity of the tomato when it hits the ground will be determined by its initial velocity, the force of gravity acting upon it, and any air resistance. It will likely be accelerating towards the ground due to gravity until it reaches its terminal velocity upon impact.
The answer will depend on what "it" is, and on what its initial velocity is.
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.