Here are the ways of rolling the dice that satisfy those conditions:
1 1
1 2
2 1
4 6
5 5
5 6
6 4
6 5
6 6
There are nine possibilities out of 36, hence, the probability is 9/36 = 1/4.
It is 15/36 = 5/12
It is 5 over 6.
Assuming these are regular dice, the probability is 1.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
The probability is 35/36.
Two standard dice cannot have a sum greater than 12. The probability, then, of getting a sum greater than 15 is zero.
If they are normal dice, the probability is 0.
It is 15/36 = 5/12
It is 5 over 6.
Assuming these are regular dice, the probability is 1.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
The probability is 35/36.
The probability is 1, if the dice are rolled often enough.
Probably.
The probability is 8/36 or 2/9
It is 1/6.
1/12 or .083