Q: When you double the first and quadruple the second integer their sum is 30 find the consecutive integers?

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Yes but a double negative integer is also positive as for example --2 = +2

The sum will be a positive integer.It will be at least as large as double the smaller integer and at most as large as double the larger integer.

If: 3x+2x = 77 Then: 5x = 77 => x = 15.4 The numbers which are not integers are: 46.2+30.8 = 77

You get a sequence of doubled triangular numbers. This sequence can also be represented by Un = n*(n + 1), [products of pairs of consecutive integers]

y is directly proportional to a, for any value of b (other than 0). If you double a, you double y; if you quadruple a, you quadruple y. Similarly, if you halve/quarter a, then you halve/quarter y.

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Yes but a double negative integer is also positive as for example --2 = +2

The sum will be a positive integer.It will be at least as large as double the smaller integer and at most as large as double the larger integer.

You you double and then you you double again.

The easiest way to do this is to use 'n' as one integer. Now, the next one needs to be consecutive, so we can make the second integer 'n+1' n + (n+1) = 55 Now all we do is start simplifying 2n + 1 = 55 2n = 55 -1 2n = 54 n = 27 Since n = 27, the first integer will be 27. And we stated that the second is 'n+1', so the second would be 28. Double check, 27 + 28 = 55 So, our integers are 27 and 28.

THE FIRST PLAYER TO ACHIEVE A QUADRUPLE DOUBLE IS NATE THURMOND

After single, double, and triple comes quadruple, which refers to four times or four-fold.

If: 3x+2x = 77 Then: 5x = 77 => x = 15.4 The numbers which are not integers are: 46.2+30.8 = 77

quadruple

sadly no

You get a sequence of doubled triangular numbers. This sequence can also be represented by Un = n*(n + 1), [products of pairs of consecutive integers]

Different computer languages use different amounts of memory to store integers. For example, C++ uses a minimum of 4 bytes, Java a min of 8 bytes. A long integer is one which is requires more bytes than the standard amount. When the storage requirement gets to twice the standard amount, the number becomes a double integer.

I'm not understanding the question. Two consecutive odd numbers will be of the form x and x+2. So simply pick the first one (hopefully you know what "odd" means and don't inadvertently pick an even number; if you're worried about this, then pick any integer at random, double it, and add one, the result is guaranteed to be odd) and add two to get the next odd number.