It is impossible to tell since there is no accompanying figure!
0 degrees (in Excel).
It is called the central angle. Hope that helped!
Try annunciating "square root" clearly.
if you have a graphing calculator you can use the inverse of Sin( and enter the number of the sides EX. push second then Sin then enter the long leg number divided by the hypotenuse and then push enter (note. this only works on right triangles)
#include "stdio.h" #include "math.h" int main() { double result,degrees,radians; printf("Enter the no. of degrees : "); scanf("%lf",&degrees); radians = degrees*(M_PI/180); result = sin(radians); printf("%lf\n",radians); printf("The sin() of %lf is %lf\n", degrees, result); return 0; }
Its angle is zero degrees.
1
0 degrees (in Excel).
On many calculators, the MODE key/button is to set the calculator into degrees or radian angle measurment, that is, when you enter a value, it and all further values you enter will then either be understood by the calculator as a degrees or radian value for an angle.
You enter at a 45 degree angle
First make sure your calculator is in 'Degree Mode (D)'. Then using the 'Inverse' of 'Sin' , shown as 'ArcSin' or ' Sin^(-1)' . enter '0.5', followed by '=' . The answer should be '30' ( 30 degrees).
To find the measurement of the fourth angle in a quadrilateral when three angles are given, you can use the property that the sum of all angles in a quadrilateral is always 360 degrees. Given that the three angles are 90, 145, and 78 degrees, you can add these together and subtract the sum from 360 to find the measurement of the fourth angle. Therefore, the fourth angle would be 360 - (90 + 145 + 78) = 47 degrees.
No, Apollo 11 did not re-enter Earth's atmosphere at a 30-degree angle. The spacecraft re-entered at a steeper angle to ensure a safe re-entry and landing.
When the incident ray is at an angle of 90 degrees to the prism, it will not enter the prism but will reflect off of it. This occurs because the light undergoes total internal reflection at the interface between the two mediums due to the critical angle being reached.
Type oke.io/ and Dz3uaand click enter, you will get your answer.
1948
When light enters or exits water into air at an angle of 15 degrees with the normal, the light ray will refract, or bend, away from the normal. This is because water is optically denser than air, causing the light to bend towards the less dense medium.