23 - x2 = sqrt(36)
23 - x2 = ±6
x2 = 17 or 29
So x ÃŽ {-5.385, -4.123, 4.123, 5.385} approx
Yes the result would be an irrational number.
3
It is a irrational number. Because the square root of every imperfect square is irrational number.
The square of a rational number can be either rational or irrational. However, the square of an irrational number is always irrational.
Yes. For example, the square root of 3 (an irrational number) times the square root of 2(an irrational number) gets you the square root of 6(an irrational number)
The result would be an irrational number
Yes the result would be an irrational number.
3
No. 1) The square root of any positive integer that doesn't happen to be a perfect square is IRRATIONAL.2) If you add a rational and an irrational number, the result is irrational.
It is a irrational number. Because the square root of every imperfect square is irrational number.
The square of a rational number can be either rational or irrational. However, the square of an irrational number is always irrational.
It is irrational, because it is not a perfect square. For example, if you have a number that is perfect like the square root of 100, it would be 10, which is a rational number. An irrational number like 16.4 which would be a not so accurate result like 6.447583839, those are irrational numbers. Hope this helps!
Yes. For example, the square root of 3 (an irrational number) times the square root of 2(an irrational number) gets you the square root of 6(an irrational number)
The square root of 27 is an irrational number
you can't FIGURE OUT THE SQUARE OF THE IRRATIONAL NUMBER
It is an irrational number.
the square root of 26 is a irrational number