The spacing between any two consecutive square numbers (n) and (n+1) is equal to (2n +1), so for 2n+1 =21, n =10 and the numbers are 121 and 100.
However, there is a non-consecutive pair as well: 25 and 4.
The squares lower than 100 are 1, 4, 9, 16, 25, 36, 49, 64, and 81, and an examination of these shows that there are no other pairs that satisfy the conditions.
when you subtract one square number with another the answer is 16 what are the two numbers
9 and 25
1 and 4?
4 and 3
25 and 4 or 121 and 100
when you subtract one square number with another the answer is 16 what are the two numbers
4 and 9
16 and 4
9 and 25
1 and 4?
5 and 2
1 and 36
That isn't possible.
4 and 3
25 and 4 or 121 and 100
The square numbers are: 16-4 = 12
16 and 25