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To achieve the result of 135 from the expression "seven squared plus one minus five times 3," you can place parentheses as follows: ( (7^2 + 1) - (5 \times 3) ). This simplifies to ( (49 + 1) - 15 ), which equals ( 50 - 15 = 35 ). However, to get 135, you could rephrase the expression as ( 7^2 + (1 - 5) \times 3 ), which evaluates to ( 49 + (-4) \times 3 = 49 - 12 = 37 ), still not yielding 135. Thus, the expression may need reevaluation or a different arrangement to meet the requirement.

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5d ago

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