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Where would you put parentheses around the following equation using the order of operations to make it true 6 minus 3 times 7 plus 4 equals 33?

It is: (6-3)*(7+4) = 33


How do you add parentheses and brackets to this equation to make it true 45 divided by 2 times 4 point 7 minus 4 point 4 times 6 equals 54?

Put a parenthesis before the 2 and after the 4.4 (2 x 4.7 - 4.4) = 9.4 - 4.4 = 5 45 divided by 5 times 6 equals 54


Where would you put parentheses around the following equation using the order of operations to make it true 13 plus 7 minus 6 plus 4 times 2 equals 0?

13 + 7 - (6 + 4) * 2 = 0


Insert parentheses when necessary to make the number a true sentence 8 minus 6 times 5 divided by 6 plus 7 equals negative 39?

8 - 6 * 5 / 6 + 7 = -39 Sorry but i can't find a solution.


How do you use 4 six times to make 100?

(444 minus 44) / 4 equals 100


Place the parentheses to make the statement true 6 plus 6 divided by 6 plus 6 times 6 equals 6?

(6 plus 6) divided by (6 plus 6) times 6 equals 6


What is a plus equals plus plus a minus minus minus a?

Your question does not make sense. It would probably be interpreted as a + = ++a ---a


Where do you put the parentheses to make 2 plus -34 equals -10?

It's 2+(-34)=-10 So put the parentheses around the -34.


What grouping symbols do you insert to make the sentence true - 5 minus 9 times 8 minus 4 equals negative 73?

5-(9x8)-4 = -71. The closest I can get


How do you make -3 plus 5 times 2 minus -6 equals 37 where would the parentheses go to make this equation true?

-3 + 5 * (2 - -6) = 37It is agreed that brackets should be calculated first and then multiplication should be carried out before addition or subtraction. Therefore:-3 + 5 * (2 - -6) = -3 + 5 * 8 = -3 + 40 = 37.


Insert parentheses to make statement true 3divide3 plus 3times3 minus 3 equals 1?

(3/3)+3*(3-3)=1 because: 3/3=1 1+3*(0)=1 due to pemdas, multiplication is first 1+0=1


How can you make VII equals I moving only one matchstick?

its impossibleAnother contributor's answer:VII minus VII = 0Removing one matchstick:VII minus VI = I