The formula is: circumference = 2 x pi x radius. As always when you use a formula, plug in the values you know and solve for the ones you don't. So plug in 46 for the circumference and solve for the radius. (You'll get that the radius = (circumference)/(2pi)).
You can solve for a one-time constant by using the formula t = RC. Read the math problem you are given carefully to determine what values to plug into the equation.
Put the equation into the following form: ax2+bx+c=0 Then plug the values for a, b, and c into the quadratic formula. Do the arithmetic to find the value for x twice, once using + after the -b in the numerator, and once using - after -b in the numerator. You will get two different values for x, one using + and the other using -. Give both possible values for x when you give your answer. Here is the quadratic formula: x= -b+-square root(b2-4ac)/2a
if you solve by plugging in the known values ahead of time you won't have a general formula for the variable in the literal equation. Therefor if the known values change, you would have to start all over again, making each problem more individualized. Once the literal equation is solved for some variable, if the known values change all you have to do is plug in those new numbers to your literal equation, and out pops your answer
You must first calculate the width, using the formula for the area of a rectangle (plug in the numbers you know into the formula, and solve for width). Once you know this, you can plug in the numbers in the formula for a rectangle's perimeter.
The formula is: circumference = 2 x pi x radius. As always when you use a formula, plug in the values you know and solve for the ones you don't. So plug in 46 for the circumference and solve for the radius. (You'll get that the radius = (circumference)/(2pi)).
No, the correct phrase is "unplug." "Plug out" is not a standard term.
Use the formula Density = Mass/Volume. If you cant plug in the values...then your professor is not doing his job well.
You can solve for a one-time constant by using the formula t = RC. Read the math problem you are given carefully to determine what values to plug into the equation.
Acceleration can be calculated using the formula: acceleration = force / mass. If the force is 50 newtons and the mass is known, plug those values into the formula to get the acceleration.
You can calculate the time to accelerate using the formula, time = (final velocity - initial velocity) / acceleration. To do this, you need to know the initial velocity, final velocity, and acceleration of the object. Plug these values into the formula to find the time it takes to accelerate.
Put the equation into the following form: ax2+bx+c=0 Then plug the values for a, b, and c into the quadratic formula. Do the arithmetic to find the value for x twice, once using + after the -b in the numerator, and once using - after -b in the numerator. You will get two different values for x, one using + and the other using -. Give both possible values for x when you give your answer. Here is the quadratic formula: x= -b+-square root(b2-4ac)/2a
This is the distance formula. Plug in your x and y values into this formula. it doesn't matter which coordinate is x1 or x2/ y1 or y2 for example: if your coordinates are (5,7) and (1,3) you can plug in: 5 for x1 and 1 for x2 then, 7 for y1 and 3 for y2 Whatever you get for d is your distance. Hope this helps! Good luck!
if you solve by plugging in the known values ahead of time you won't have a general formula for the variable in the literal equation. Therefor if the known values change, you would have to start all over again, making each problem more individualized. Once the literal equation is solved for some variable, if the known values change all you have to do is plug in those new numbers to your literal equation, and out pops your answer
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Plug the x-values into the original equation. If you get the same y-values, then the points are valid.