Slightly to the right of 2. If you get to 3, you've gone too far.
One-third, or ( \frac{1}{3} ), is located to the right of 0 and to the left of 1 on a number line. It is positioned one-third of the way between 0 and 1, dividing the interval into three equal parts. You can visualize it by marking the points 0, ( \frac{1}{3} ), ( \frac{2}{3} ), and 1 on the line.
The only number that will equal -1 on a number line is -1 .
Halfway between 9 and 1/2 and 10.
Between 0 and 1. More than halfway from 1: in fact, exactly two thirds of the way between 0 and 1.
On a number line, 0.6 is located between 0 and 1. It is slightly closer to 1 than to 0, positioned at the six-tenths mark. To visualize it, you can divide the segment between 0 and 1 into ten equal parts, where 0.6 would be the sixth division from 0.
0.7 is located on the number line between 0 and 1.
between 0 and 1
One-third, or ( \frac{1}{3} ), is located to the right of 0 and to the left of 1 on a number line. It is positioned one-third of the way between 0 and 1, dividing the interval into three equal parts. You can visualize it by marking the points 0, ( \frac{1}{3} ), ( \frac{2}{3} ), and 1 on the line.
The only number that will equal -1 on a number line is -1 .
Halfway between 9 and 1/2 and 10.
1/4 is equivalent to 0.25 on the number line
Between 0 and 1. More than halfway from 1: in fact, exactly two thirds of the way between 0 and 1.
Between 1 and 2, a quarter of the way along from 1.
As there is only one number this would be located on the number line. The location being one quarter of the distance between -1 and -2. The scale of the line can be arbitrary so long as it includes as much of the line to show the number and a reference to 0 (zero)
On a number line, 0.6 is located between 0 and 1. It is slightly closer to 1 than to 0, positioned at the six-tenths mark. To visualize it, you can divide the segment between 0 and 1 into ten equal parts, where 0.6 would be the sixth division from 0.
To find the number of marbles in the sixth line using the given rule, we start with the first line having 2 marbles. Each subsequent line has a number of marbles that is one less than twice the previous line. Following this pattern: 1st line: 2 2nd line: (2 * 2) - 1 = 3 3rd line: (2 * 3) - 1 = 5 4th line: (2 * 5) - 1 = 9 5th line: (2 * 9) - 1 = 17 6th line: (2 * 17) - 1 = 33 Thus, there must be 33 marbles in the sixth line.
The mixed number 1 11/12 can be converted to an improper fraction by multiplying the whole number (1) by the denominator (12) and adding the numerator (11), resulting in 23/12. On a number line, 1 11/12 would be located just before the number 2, specifically between 1.9 and 2.0, as it is slightly less than 2.