Take a map S from set A to set B, denote S: A ---> B We call A to be our domain, B our codomain. We call, with an small abuse of notation, S(A) our range, that is the set of all maps of elements of A. Or, we call set C the range of S if C = {c | c = S(a) for all a from A} Remark, C is a subset of B. Just for further knowledge, if for all a in A, S(a) is different, or S(a) != S(b) => a != b for all a, b from A (S(a) and S(b) from B), then we say S is one-to-one. It can happen when the "size" of A is smaller or equal than that of B. if the range of S is the same as the codomain. Or for all elements c from B, c = S(a) for some a from A, then we call S to be onto. It can happen when "size" of A is larger or equal to that of B. Further, if S is one-to-one AND onto, it is invertible. I will leave the proof as an exercise. Just two more note: 1. S is linear if it's a map between vector space A, B over field F which also satisfies S(a + b) = S(a) (+) S(b) and S(kb) = k.S(b) where + and x are addition and scalar multiplication from A while (+) and . are for B. 2. S is not necessarily a function.
Use the Hero's formula: Let s = (a + b + c)/2. Then the area of the triangle equals√[s(s - a)(s - b)(s - c)], where a, b, and c denote the sides of the triangle.
Let the sides be a, b, c Area = sq rt [s(s-a)(s-b)(s-c)] where s= 1/2 (a+b+c)
The answer depends on the information that you do have. Suppose you know all the edge lengths: the three sides of the triangle are a, b and c and the length of the prism is d. Let s = (a + b + c)/2 Then the area of the triangular cross section is sqrt[s*(s-a)*(s-b)*(s-c)] square units. So, surface area = 2*sqrt[s*(s-a)*(s-b)*(s-c)] + d*(a+b+c) square units. Volume = sqrt[s*(s-a)*(s-b)*(s-c)]*d cubic units.
120 sq metres. To see how you get this answer, read on: If the sides are a, b and c, then calculate s = 0.5*(a+b+c) Then the area is sqrt[s*(s-a)*(s-b)*(s-c)]
Kaia Kruus has written: 'A proposed interface design for a multi-target database searcher' -- subject(s): Design, Computer interfaces, Online library catalogs
Im taking ms for m/s. the magnitude of the impulse= (px)i=m(vxi)=(0.145kg)(-15.0m/s)=-2.2N (px)f=m(vx)f=(0.145kg)(20.0m/s)=2.9N Delta Px =(px)f-(px)i= 2.9N-(-2.2N)=5.1N or 5.1 kg m/s If the bat is in contact with the ball for 1.5 ms the magnitude of the avg force exerted on the bat is: Favg= J/Delta t 1.5 ms=0.0015 s Favg= (5.1 kg m/s)/0.0015 = 3400N
The Army does not supply them to you, but they can be purchased at the Post Exchange (PX) store(s) located on base.
Malcolm. Taylor has written: 'The actor and the camera' -- subject(s): Acting, Television acting, Vocational guidance 'PX'
The ditloid 7 equals B for S B (7 = B for S B) means:7 = Brides for Seven Brothers
S. B. S. Abayakoon was born in 1958.
The next letter will be a "b." The pattern 2-1-3-2-4-3-etc. So the "a"s and "b"s will each increase by one. First there were two "b"s, then one "a." Then there were three "b"s and two "a"s. So next there will be four "b"s and three "a"s, five "b"s and four "a"s, and so on.
Take a map S from set A to set B, denote S: A ---> B We call A to be our domain, B our codomain. We call, with an small abuse of notation, S(A) our range, that is the set of all maps of elements of A. Or, we call set C the range of S if C = {c | c = S(a) for all a from A} Remark, C is a subset of B. Just for further knowledge, if for all a in A, S(a) is different, or S(a) != S(b) => a != b for all a, b from A (S(a) and S(b) from B), then we say S is one-to-one. It can happen when the "size" of A is smaller or equal than that of B. if the range of S is the same as the codomain. Or for all elements c from B, c = S(a) for some a from A, then we call S to be onto. It can happen when "size" of A is larger or equal to that of B. Further, if S is one-to-one AND onto, it is invertible. I will leave the proof as an exercise. Just two more note: 1. S is linear if it's a map between vector space A, B over field F which also satisfies S(a + b) = S(a) (+) S(b) and S(kb) = k.S(b) where + and x are addition and scalar multiplication from A while (+) and . are for B. 2. S is not necessarily a function.
It is sqrt{s*(s-a)*(s-b)*(s-c)} where the lengths of the three sides are a, b and c units and s = (a+b+c)/2.
B. S. Chandrasekhar was born in 1945.
B. S. Potter was born in 1836.
S. B. Rao was born in 1943.