It's at the point ( -5, 3 )
The general formula of a circle is given by the equation:
( x - h )2 + ( y - k )2 = r2
Where the point ( h, k ) is the center of the circle, and r is the radius of the circle. In the equation
( x + 5 )2 + ( y - 3 )2 = 25
The first group of terms isn't subtracted. Rather than x + 5, this is actually x - -5.
The center of the circle, then, is the point ( -5, 3 )
(-4,-6)
The centre is (-5, 3)
Exactly as it's stated, that equation describes a straight line, not a circle. If you take out the phrase "times 2" from both places where it's used and replace it with "squared", then the equation describes a circle, centered at (-5, 3), with a radius of 5.
(-4,3)
depends on the equation.
A unit circle is a circle of radius 1. If it's center is at the origin of an xy-coordinate system, then the equation is x (squared) + y (squared) = 1
I think this means (x+7)squared + (y-5)squared =4squared, which represents a circle centred at -7,+5
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
(-4,-6)
The center of the circle is at (-7, 5)
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
The centre is (-5, 3)
Exactly as it's stated, that equation describes a straight line, not a circle. If you take out the phrase "times 2" from both places where it's used and replace it with "squared", then the equation describes a circle, centered at (-5, 3), with a radius of 5.
General formula for a circle is X squared + Y squared = radius squared. So the answer would be x squared + y squared = 2.64575131 squared
It is: (x-a)^2 +(y-b)^2 = m squared
This is the equation of a semi-circle, or a half circle.
The equation for the circumference of a circle is pi times radius squared.