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It's at the point ( -5, 3 )

The general formula of a circle is given by the equation:

( x - h )2 + ( y - k )2 = r2

Where the point ( h, k ) is the center of the circle, and r is the radius of the circle. In the equation

( x + 5 )2 + ( y - 3 )2 = 25

The first group of terms isn't subtracted. Rather than x + 5, this is actually x - -5.

The center of the circle, then, is the point ( -5, 3 )

Q: Where is the center of the circle given by the equation x plus 5 squared plus y minus 3 equals 25 Enter your answer as an ordered pair?

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(-4,-6)

The centre is (-5, 3)

Exactly as it's stated, that equation describes a straight line, not a circle. If you take out the phrase "times 2" from both places where it's used and replace it with "squared", then the equation describes a circle, centered at (-5, 3), with a radius of 5.

(-4,3)

depends on the equation.

Related questions

A unit circle is a circle of radius 1. If it's center is at the origin of an xy-coordinate system, then the equation is x (squared) + y (squared) = 1

I think this means (x+7)squared + (y-5)squared =4squared, which represents a circle centred at -7,+5

The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).

(-4,-6)

The center of the circle is at (-7, 5)

You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)

The centre is (-5, 3)

Exactly as it's stated, that equation describes a straight line, not a circle. If you take out the phrase "times 2" from both places where it's used and replace it with "squared", then the equation describes a circle, centered at (-5, 3), with a radius of 5.

General formula for a circle is X squared + Y squared = radius squared. So the answer would be x squared + y squared = 2.64575131 squared

It is: (x-a)^2 +(y-b)^2 = m squared

This is the equation of a semi-circle, or a half circle.

The equation for the circumference of a circle is pi times radius squared.