10.01 is less than 10.1
122
10.1
1110
a)5b39+39a2=101 1011 0011 1001+11 1001 1010 0010=1001 0100 1101 1011 af=0 sf=1 zf=0 cf=0 b)5b39+dc49=101 1011 0011 1001+1101 1100 0100 1001=1 0011 0111 1000 0010 af=1 sf=0 zf=0 cf=1
There are infinitely many answers: any polygon with 6. 7, 8, 9, ... 100, 101, 102, ... 1000, 1001, 1002, ... , 1000000, 1000001 sides and the list continues forever.There are infinitely many answers: any polygon with 6. 7, 8, 9, ... 100, 101, 102, ... 1000, 1001, 1002, ... , 1000000, 1000001 sides and the list continues forever.There are infinitely many answers: any polygon with 6. 7, 8, 9, ... 100, 101, 102, ... 1000, 1001, 1002, ... , 1000000, 1000001 sides and the list continues forever.There are infinitely many answers: any polygon with 6. 7, 8, 9, ... 100, 101, 102, ... 1000, 1001, 1002, ... , 1000000, 1000001 sides and the list continues forever.
Least common multiple for 1001 and 13 is 1001.
122
LCM(77, 1001) = 1001
1110
10.1
10^n+1
100 1000 100 0001 101 0110 100 0101 100 0001 100 1110 100 1001 100 0011 100 0101 100 0100 100 0001 101 1001---------Binary Representation. 110 101 126 105 101 116 111 103 105 104 101 131.------Octal
1 10 11 100 101 110 111 1000 1001 1010 1011 1100 ...1 10 11 100 101 110 111 1000 1001 1010 1011 1100 ...1 10 11 100 101 110 111 1000 1001 1010 1011 1100 ...1 10 11 100 101 110 111 1000 1001 1010 1011 1100 ...
1
1,001
a)5b39+39a2=101 1011 0011 1001+11 1001 1010 0010=1001 0100 1101 1011 af=0 sf=1 zf=0 cf=0 b)5b39+dc49=101 1011 0011 1001+1101 1100 0100 1001=1 0011 0111 1000 0010 af=1 sf=0 zf=0 cf=1
You need at least two numbers to find a GCF.