10.01 is less than 10.1
122
1110
10.1
The smallest 4-digit palindrome is 1001. To find if it can be expressed as the sum of two 3-digit palindromes, consider the smallest 3-digit palindromes, which are 101, 111, 121, etc. The combination of 101 and 900 (another 3-digit palindrome) gives 1001, making 1001 the sum of two 3-digit palindromes. Thus, the answer is 1001.
a)5b39+39a2=101 1011 0011 1001+11 1001 1010 0010=1001 0100 1101 1011 af=0 sf=1 zf=0 cf=0 b)5b39+dc49=101 1011 0011 1001+1101 1100 0100 1001=1 0011 0111 1000 0010 af=1 sf=0 zf=0 cf=1
Least common multiple for 1001 and 13 is 1001.
122
LCM(77, 1001) = 1001
1110
10.1
100 1000 100 0001 101 0110 100 0101 100 0001 100 1110 100 1001 100 0011 100 0101 100 0100 100 0001 101 1001---------Binary Representation. 110 101 126 105 101 116 111 103 105 104 101 131.------Octal
1 10 11 100 101 110 111 1000 1001 1010 1011 1100 ...1 10 11 100 101 110 111 1000 1001 1010 1011 1100 ...1 10 11 100 101 110 111 1000 1001 1010 1011 1100 ...1 10 11 100 101 110 111 1000 1001 1010 1011 1100 ...
1
The smallest 4-digit palindrome is 1001. To find if it can be expressed as the sum of two 3-digit palindromes, consider the smallest 3-digit palindromes, which are 101, 111, 121, etc. The combination of 101 and 900 (another 3-digit palindrome) gives 1001, making 1001 the sum of two 3-digit palindromes. Thus, the answer is 1001.
1,001
a)5b39+39a2=101 1011 0011 1001+11 1001 1010 0010=1001 0100 1101 1011 af=0 sf=1 zf=0 cf=0 b)5b39+dc49=101 1011 0011 1001+1101 1100 0100 1001=1 0011 0111 1000 0010 af=1 sf=0 zf=0 cf=1
You need at least two numbers to find a GCF.