Q: Where to buy 5 foot diameter rubber inner tube?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

We need to know the dimensions of the tube. The diameter AND the length of the tube. It takes o.465 yards per foot of length for a tube 4 feet in diameter. .

$ = (K) times (LD), 'K' is some constant. 10-ft of 1-inch tube: L D = 10 15-ft of 2-inch tube: L D = 30 Since (LD) has tripled, $ = 3 x 5.80 = $17.40

if you mean a cylinder with a hole through it like a pipe or tube, then it's pi x (Od2 - id2)/4 x h Od = outer diameter id = inner diameter

That depends on the thickness or diameter of the tube.

Yes

Related questions

The medical term for the inner diameter of a tube is "lumen."

An inner tube is a rubber torus. Like a hula hoop but out ot rubber.

Inner tubes are made from butyl rubber. Or sometimes latex.

A hose is usually made of plastic or rubber. A pipe, on a motor vehicle is made of metal,steel, copper , galvanised. A tube is also made of metal ,but has a much thinner wall . (ie the difference between the outer diameter and the inner diameter)

Inner tube rubber is typically made from a type of synthetic rubber that is considered non-toxic. However, burning rubber, such as from an inner tube, can release harmful chemicals and should be avoided.

We need to know the dimensions of the tube. The diameter AND the length of the tube. It takes o.465 yards per foot of length for a tube 4 feet in diameter. .

Rubber- similar to an inner tube or tire.

The inner tube for bicycle tires was invented by John Boyd Dunlop in 1888. He developed the inner tube to provide cushioning for the rubber tires, resulting in a smoother and more comfortable ride for cyclists.

Sure, the inner tube is just a stretchy rubber bladder. It'll expand until the tire stops it.

To calculate the mass of a hollow tube, you need to know the outer diameter, inner diameter, and length of the tube. First, calculate the volume of the tube by subtracting the volume of the inner hole from the volume of the outer cylinder. Then, multiply the volume by the density of the material to determine the mass.

$ = (K) times (LD), 'K' is some constant. 10-ft of 1-inch tube: L D = 10 15-ft of 2-inch tube: L D = 30 Since (LD) has tripled, $ = 3 x 5.80 = $17.40

.088 cf