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Do parenthesis make a difference in exponent equations?
HELLZ YA what if it were something like this: 0=(9x-4)^1/2 if there were no parenthesis the answer would be totally different you have to distribute the exponent. in this case, the exponent is a fraction meaning you actually take the root
What do parenthesis or brackets stand for in algebra?
That everything within the brackets will get calculated first. So if you'd have (5*2)+3, the part in the brackets would get calculated first. So it would actually make it 10+3
How is eleven squared different from parenthesis eleven squared?
Please Excuse My Dear Aunt Sally... PEMDAS P = parenthesis E = Exponent M = Multiply D = Divide A = Add S = Subtract In other words, order of operation as it is know in mathematics. So coming full circle to your question, parenthesis are typically reserved in equations force a portion of a calcuation to be completed before another, i.e. 1+2*3=7, while (1+2)*3=9. In the second equation, parenthesis are inserted to make sure the addtion is completed prior to the multipication. However, in the question you pose the answer would be the same. (11)^x = 11^x All that said, if the parenthesis in question in in a line of software code, most programs will only connect the term immediately before the carrot "^" as being raised to the power. So a program would read 11^x as 1*1^x instead of (11)^x, thus the need for the parenthesis.
How do you factor q2-7q plus 12?
1. When factoring first always look for a GCF (greatest common factor). If each term has a greatest common factor, factor it out in from using parenthesis first. This problem does not have a GCF. 2. Next, since this is a trinomial, many times we can factor it down using backwards FOIL (First, Outter, Inner, Last). 3. To do this always put down two sets of parenthesis. (we do this because we are looking to factor into two binomials) ( )( ) 4. Next we complete the fist term in each set of parenthesis. The first term is simply going to be the variable we are using in the problem. In this problem the variable is q. (q )(q ) 5. Then find the factors of the last term (+12) in which the sum is equal to the coefficient of the middle term (-7). These factors are -3 and -4. 6. Complete the factoring by putting these factors into the second part of the parenthesis. (q - 3)(q - 4) * If you want to make sure you are correct, multiply you answer out and see if you get the same trinomial you started with.
How do you insert grouping symbols to make this number sentence true - Order of operations 4 times 6 subtract 2 plus 7 23?
The grouping of symbols and number of 4 times 6 subtract 2 plus 7 equals 23 would look like 4(6-2)+7=23. Remember the problem with the in parenthesis should be completed first.
