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8+9+10+11
8 and 9
6+7+8+9=30
Let's denote the three consecutive numbers as x, x+1, and x+2. We can set up the equation x + (x+1) + (x+2) = 27. By simplifying, we get 3x + 3 = 27. Solving for x gives us x = 8. Therefore, the three consecutive numbers are 8, 9, and 10.
8 + 9 + 10 + 11 = 38 9 + 10 + 11 + 12 = 42 So, unless this is a trick question, there are not 4 consecutive numbers that sum to 40.