-7-6-5-4-3-2-1-0+1+2+3+4+5+6+7+8
8+9+10+11
8 and 9
6+7+8+9=30
The two consecutive cube numbers that add up to 1241 are (10^3) (1000) and (11^3) (1331). However, their sum is 2331, which is too high. Instead, the correct consecutive cube numbers are (9^3) (729) and (10^3) (1000). Their sum is 1729, also incorrect. The correct consecutive cube numbers are (9^3) (729) and (8^3) (512), which add up to 1241.
Let's denote the three consecutive numbers as x, x+1, and x+2. We can set up the equation x + (x+1) + (x+2) = 27. By simplifying, we get 3x + 3 = 27. Solving for x gives us x = 8. Therefore, the three consecutive numbers are 8, 9, and 10.
No.
There are no three consecutive numbers that add up to twenty.Proof:5+6+7=186+7+8=217+8+9 = 24
There is no set of 8 consecutive whole numbers whose sum is 75.
17
8+9+10+11
8 and 9
6+7+8+9=30
27
5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 = 68
It's impossible! to say that this question is impossible the odd numbers are 7 8 9 7+8+9=24
Let's denote the three consecutive numbers as x, x+1, and x+2. We can set up the equation x + (x+1) + (x+2) = 27. By simplifying, we get 3x + 3 = 27. Solving for x gives us x = 8. Therefore, the three consecutive numbers are 8, 9, and 10.
The formula for this is x + (x+2) + (x+4) = 18 3x + 6 = 18 3x = 12 x = 4 So the three consecutive even numbers are 4, 6, and 8, which add up to 18.