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What does odd divided by even always equal?
Odd divided by even will always be a decimal. The answer will not be an integer.
The sum of an even integer and an odd integer is always odd?
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Even plus odd is odd.
Is an odd number always an irrational number?
No. In fact, no odd integer is irrational. They are all rational.
Why when you add even and odd is always odd?
all even numbers can be written in the form 2k where, k is an integer. all odd numbers can be written in the form 2j+1, where j is an integer. 2k + 2j + 1 = 2(k+j) + 1. You can see that this is in the form of an odd number. hence, the sum of an odd number and an even number is always odd. Test the theory. Pick any even and any odd number. Add them. The total will always be odd.
Can the sum of an odd and even number be odd?
Yes, 1+2=3 and since 1 is odd and 2 is even this shows it can happen. In fact it always does! If we let an even number be denoted by 2n for some integer n and and an odd one 2m+1 for some integer m. Then, 2m+1+2n=2(m+n)+1. Call m+n, p since it is also an integer. 2p+1 is always odd.
What are the three consecutive odd integers with sum of -30?
It cannot be done. The basic rules of math. odd integer plus odd integer = even integer. odd integer plus even integer = odd integer. Always. odd integer plus odd integer plus odd integer = odd integer. Always.
What does odd divided by even always equal?
Odd divided by even will always be a decimal. The answer will not be an integer.
How do you use inductive reasoning to prove the product of an odd integer and an even integer will always be even?
The product of an odd and even number will always have 2 as a factor. Therefore, it will always be even.
The sum of an even integer and an odd integer is always odd?
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Even plus odd is odd.
Is an odd number always an irrational number?
No. In fact, no odd integer is irrational. They are all rational.
Why is the sum always odd when you add an even and an odd number?
An even integer is a multiple of 2 so that if x is the even integer then there is some other integer a such that x = 2a. An odd integer is one which, when you divide it by 2, leaves a remainder of 1. That is, if y is the odd integer, then y = 2b + 1 for some other integer b. Now, the sum of the even and odd integer is x + y = 2a + 2b + 1 = 2(a+b) + 1 By the closure of integers under addition, a and b are integers implies that a+b is an integer. So 2(a+b) is even and so the sum is odd.
Why when you add even and odd is always odd?
all even numbers can be written in the form 2k where, k is an integer. all odd numbers can be written in the form 2j+1, where j is an integer. 2k + 2j + 1 = 2(k+j) + 1. You can see that this is in the form of an odd number. hence, the sum of an odd number and an even number is always odd. Test the theory. Pick any even and any odd number. Add them. The total will always be odd.
When you multiply an odd number by an odd number is the answer always odd?
Yes - while multiplying odd numbers by even numbers will always produce an even result.
What four numbers that are odds equal thirteen?
Adding four odd integers will produce an even integer, and 13 is odd; so it can't be done.
What two integers add up to -12 but their difference is 1?
-- If their difference is 1, then one of them is even and the other one is odd. -- The sum of (an even integer) plus (an odd integer) is always odd. -- (-12) is not odd. So we're going to say that the question has no solution.
Can the sum of an odd and even number be odd?
Yes, 1+2=3 and since 1 is odd and 2 is even this shows it can happen. In fact it always does! If we let an even number be denoted by 2n for some integer n and and an odd one 2m+1 for some integer m. Then, 2m+1+2n=2(m+n)+1. Call m+n, p since it is also an integer. 2p+1 is always odd.
What is the 17th odd positive integer?
33 The 17th odd positive integer is
