4/3 pie(7exponent3)
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Surface area of a sphere: 4*pi*r^2
( The volume of a sphere is (4/3)(pi)r3 ). The short answer: because of calculus. The long answer: This can be seen by using calculus to derive the volume of a sphere from the formula from it's surface area. To do this, we imagine that the sphere is full of infinity thin spheres inside it (all centered at the big sphere's center), and add up the surface areas of all the spheres inside. The formula for the surface area of a sphere is 4(pi)r2. Let's call R the radius of the big sphere we want to find the volume of. To find the volume of this sphere, we add up the surface areas of all the spheres whose radii range from 0 to R. This gives the following formula (where r is the radius of each little sphere): 0R∫ 4(pi)r2dr The 4 and pi can be factored out giving: 4(pi) (0R∫r2dr) Integrating gives: 4(pi) [r3/3]0R This is where the three comes from. Finishing the evaluation of the integral gives: 4(pi)(R3/3 - 03/3) = 4(pi)(R3/3) Which can be rewritten as (4/3)pi(R3) which is the formula for the volume of a sphere.
Volume: 4/3*pi*radius3 = 140 By making the radius the subject of the above gives it a value of 3.221166265 cm Surface area: 4*pi*3.2211662652 = 130.387557 square cm
To find the surface area of a sphere when its volume is 288π cubic cm, we first need to find the radius of the sphere. The formula for the volume of a sphere is V = (4/3)πr^3, where r is the radius. Given that the volume is 288π, we can solve for r: 288π = (4/3)πr^3. Solving for r, we get r = 6 cm. Next, we can find the surface area of the sphere using the formula A = 4πr^2, where r is the radius. Plugging in the radius of 6 cm, we get A = 4π(6)^2 = 144π square cm. Therefore, the surface area of the sphere is 144π square cm.
The volume of a cone is pi(r2h)/3 If the radius and height are both tripled, plugging this into the equation gives us pi(3h(3r)2)/3 =pi(3h9r2)/3 =27pi(r2h)/3 which is 27 times the initial volume. Thus if the radius and height of a cone are tripled, the volume multiplies by 27.