If X takes the value 1 with probability p and 0 with probability (1-p), and there are n independent trials then E(X) = np
Expected value is the outcome of confidence of how probability distribution is characterized. If the expected value is greater than the confidence interval then the results are significant.
No. I am using "normalization" as used in probability theory as application of a normalizing constant to a value, to make it conform to a certain distribution.
Yes it can be negative.
Almost all statistical distribution have a mean. It is the expected value of the random variable which is distributed according to that function.
Yes, it is true.
Consider a binomial distribution with 10 trials What is the expected value of this distribution if the probability of success on a single trial is 0.5?
average number of successes
It is the expected value of the distribution. It also happens to be the mode and median.It is the expected value of the distribution. It also happens to be the mode and median.It is the expected value of the distribution. It also happens to be the mode and median.It is the expected value of the distribution. It also happens to be the mode and median.
The expected value is the average of a probability distribution. It is the value that can be expected to occur on the average, in the long run.
It is a binomial expression.
Expected value is the outcome of confidence of how probability distribution is characterized. If the expected value is greater than the confidence interval then the results are significant.
The expected value of the standard normal distribution is equal to the total amount of the value. It is usually equal to it when the value works out to be the same.
No. I am using "normalization" as used in probability theory as application of a normalizing constant to a value, to make it conform to a certain distribution.
(5n - 20) It's a binomial expression in 'n'. Its numerical value depends on the numerical value of 'n'.
30.47
Yes it can be negative.
This is the answer.