If you mean: y2+5y+6 then it is (y+2)(y+3) when factored completely
This is a special kind of expression called a difference of squares. Anything in the format a2 - b2 can be factored out as (a + b)(a - b). So we can say: x2 - 25y2 = x2 - (5y)2 = (x + 5y)(x - 5y)
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To simplify the expression (21x + 35y + 14), we can factor out the greatest common factor (GCF) of the coefficients. The GCF of 21, 35, and 14 is 7. Thus, the expression can be factored as (7(3x + 5y + 2)).
The expression (3x^3 + 5y^3 + 14) is already in its simplest form, as it consists of distinct terms that cannot be combined or factored further. Each term has different variables and powers, preventing any simplification through addition or factoring. Therefore, there are no common factors or like terms to simplify in this expression.
25xy+5yz is 5y(5x+z) when factored
You can use the formula for the difference of two squares in this case. - In general, for factoring, check whether the expression to be factored corresponds to one of several common forms - as in this case.
This is a special kind of expression called a difference of squares. Anything in the format a2 - b2 can be factored out as (a + b)(a - b). So we can say: x2 - 25y2 = x2 - (5y)2 = (x + 5y)(x - 5y)
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25xy is an equivalent expression.
To simplify the expression (21x + 35y + 14), we can factor out the greatest common factor (GCF) of the coefficients. The GCF of 21, 35, and 14 is 7. Thus, the expression can be factored as (7(3x + 5y + 2)).
The expression (3x^3 + 5y^3 + 14) is already in its simplest form, as it consists of distinct terms that cannot be combined or factored further. Each term has different variables and powers, preventing any simplification through addition or factoring. Therefore, there are no common factors or like terms to simplify in this expression.
25xy+5yz is 5y(5x+z) when factored
The expression "5y plus 35" can be written mathematically as 5y + 35. This represents a linear equation where 5y is the variable term and 35 is the constant term. The value of this expression will depend on the value assigned to y.
It's an algebraic expression that can be simplified to: x-5y
It is an algebraic expression
5y - 65xy '5' is a common factor both numbers. Hence 'take it out'. 5(y - 13xy) 'y' is a common factor to both terms, so take it out too!!!! 5y(1 - 13x) Done Factored!!!!!
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