Find the two X intercepts. Set = to 0 4X + 3 = 0 X = -3/4 ( while Y = 3) 4X - 2 = 0 X = 1/2 ( while Y = -2) Now you have two points for each parallel line and can draw the graph
6 - 4x = 13 So 4x = -7 or x = -7/4 = -1.75 In 1-dimension, the graph would consist of the single point x = -1.75 In 2-dimensions, the graph would consist of the vertical line, passing through x = -1.75 In 3-dimensions, the graph would consist of the plane parallel to the y-z axes and passing through x = -1.75
y = -x2 - 4x - 3. The constant, 3, tells us where the graph would hit the y-axis. In this case, it would hit the y-axis at -3. Solving the equation y = -(x2 + 4x + 3) ; y=-(x+3)(x+1) Therefore hits the x-axis at -3 and -1. Since it's a parabola (x2), the graph can either start from the top, or from the bottom. An equation starting with ax2 will start from the top, and an equation with -ax2 will start from the bottom. So therefore, the graph starts from the bottom of the page, goes from -3 and -1 on the x-axis and intercepts the y-axis at -3.
4x - 3y = 12-3y = -4x + 12y = (4/3)x - 4^plug this transformed version of the equation into your graphing calculator or do it out by hand.
If x = 3, 4x = 12
Find the two X intercepts. Set = to 0 4X + 3 = 0 X = -3/4 ( while Y = 3) 4X - 2 = 0 X = 1/2 ( while Y = -2) Now you have two points for each parallel line and can draw the graph
6 - 4x = 13 So 4x = -7 or x = -7/4 = -1.75 In 1-dimension, the graph would consist of the single point x = -1.75 In 2-dimensions, the graph would consist of the vertical line, passing through x = -1.75 In 3-dimensions, the graph would consist of the plane parallel to the y-z axes and passing through x = -1.75
4x - 3y = -6Add 3y to each side:4x = -6 + 3yAdd 6 to each side:4x + 6 = 3yDivide each side by 3:(4/3)x + 2 = yThe graph is a straight line with a slope of (4/3) and a y-intercept of 2 .
(4x2 - 13x - 12)/(4x+ 3) = (4x + 3)(x - 4)/(4x + 3) = (4x + 3)(x - 4)/(4x + 3) = x - 4 :)
y = -x2 - 4x - 3. The constant, 3, tells us where the graph would hit the y-axis. In this case, it would hit the y-axis at -3. Solving the equation y = -(x2 + 4x + 3) ; y=-(x+3)(x+1) Therefore hits the x-axis at -3 and -1. Since it's a parabola (x2), the graph can either start from the top, or from the bottom. An equation starting with ax2 will start from the top, and an equation with -ax2 will start from the bottom. So therefore, the graph starts from the bottom of the page, goes from -3 and -1 on the x-axis and intercepts the y-axis at -3.
7
4x - 3y = 12-3y = -4x + 12y = (4/3)x - 4^plug this transformed version of the equation into your graphing calculator or do it out by hand.
y=xsquared-4x+2
If x = 3, 4x = 12
(-4x-6)-(-x-3)
You may mean, what is the graph of the function y = x^2 + 3. This graph shows a upward parabola with a y-intercept of 3 and a minimum at x=0.
4x + 3 = 47 4x = 47-3 4x = 44 x = 44/4 x = 11