Are you kidding ? Neither of them belongs to this group.
The circle is out because it's the only one in the group without straight sides.
The square is out because it's the only one in the group with straight sides.
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Yes. One has to be the square of an odd number. The other square has to the the square of the even number either before or after the odd number. If this is confusing just plug in real values. In either case, an odd times and odd is odd. Therefore one of the squares has to be odd. AN even times an even, however, is always even. Therefore, the second square has to be even. Thus, one of the squares is even and the other is odd. An even plus and odd is always odd.
1/3.15159
odd
no, it is odd
The is not stated that the circle inside the square was the greatest possible circle, so all one can say is 8pi at most.