4*100 + 8*10 + 1
To represent the number 4200 using place-value blocks, you would need 4 thousands blocks (for the 4000), 2 hundreds blocks (for the 200), and no tens or ones blocks. Therefore, the least number of place-value blocks needed is 6. This includes 4 blocks for the thousands and 2 blocks for the hundreds.
(-3) -8- (-7)=
To model multiplying decimals using base ten blocks, you can represent each decimal as a fraction of the blocks. For example, if you are multiplying 0.3 by 0.4, use 3/10 of a flat (representing 0.3) and 4/10 of a flat (representing 0.4). Arrange these sections to show that the product is found by taking the area of the overlapping blocks. In this case, the product would be 0.12, represented by the smaller blocks formed from the overlap.
Use 1374 hundred blocks = 137400 Two ten blocks = 20 Nine one blocks = 9 Total = 137429.
bye using five or more
What is the least number of place-value blocks that you need to show 3,010? The least number is four: One Tens block, and three Thousands blocks. The greatest number would be 3,010: All Ones value blocks.
No, it's impossible. If you did it with hundredths blocks then it would be fair.
No. In that case it is 0.0
(-3) -8- (-7)=
No, it's impossible. If you did it with hundredths blocks then it would be fair.
(2x100)+(15x4)+(7x1)=200+60+7=267
59.5
nineteen
no, it's impossible unless your using the hundredths place.
The Hayseeds' Back-blocks Show was created on 1917-11-05.
18/10
To model multiplying decimals using base ten blocks, you can represent each decimal as a fraction of the blocks. For example, if you are multiplying 0.3 by 0.4, use 3/10 of a flat (representing 0.3) and 4/10 of a flat (representing 0.4). Arrange these sections to show that the product is found by taking the area of the overlapping blocks. In this case, the product would be 0.12, represented by the smaller blocks formed from the overlap.