Factor out each number into primes to get: 38 = 2 * 19 20 = 2² * 5 28 = 2² * 7 Count the maximum number of distinct primes for all of these values. For instance, if 20 and 28 both have the maximum number of "2" 2, then write out 2². If one number has a prime factor while the rest of the number doesn't, then write out that prime factor. Following these steps, we have this product: 2² * 5 * 19 * 7 = 4 * 5 * 7 * 19 = 2660 So that is the LCM of the given numbers.
No since it is an even number it has 2 as a factor. If the factors are the number itself and 1 it is prime. If there are more factors it is not. 28 has many more factors.28=22 x7So 2 and 4 and 7 are all factors as is 14.
Their only prime factor is 4.
I think you misworded your question. I am not exactly sure what you are looking for. If you want to know the prime factorization of the number 28, it is, 2^2 * 7. That is two squared times seven.
7,2,2 14,2 28
Because 7 is a factor of 28 and 63 and 7 is a prime number.
No, 1 is not a prime number.
1, 4, 14, 28
It is: 7
2 and 7
Yes it's a factor of 28 for example and it's a prime number
28 is a factor of 28, as 28/28 = 1. 28 is also a multiple of 28, as 28*1 = 28.
The least common prime factor of 24 and 28 is 2.
The highest common factor of both number is 28
Prime factor each number. Circle all the prime common factors then, multiply them 28=2x2x7 32=2x2x2x2x2 GCF=2x2=4
28 has two prime factors: 2 and 7.
28 (22*7)