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Factor out each number into primes to get: 38 = 2 * 19 20 = 2² * 5 28 = 2² * 7 Count the maximum number of distinct primes for all of these values. For instance, if 20 and 28 both have the maximum number of "2" 2, then write out 2². If one number has a prime factor while the rest of the number doesn't, then write out that prime factor. Following these steps, we have this product: 2² * 5 * 19 * 7 = 4 * 5 * 7 * 19 = 2660 So that is the LCM of the given numbers.
No since it is an even number it has 2 as a factor. If the factors are the number itself and 1 it is prime. If there are more factors it is not. 28 has many more factors.28=22 x7So 2 and 4 and 7 are all factors as is 14.
Their only prime factor is 4.
I think you misworded your question. I am not exactly sure what you are looking for. If you want to know the prime factorization of the number 28, it is, 2^2 * 7. That is two squared times seven.
7,2,2 14,2 28