Which number when 1.divided by 9 gives remainder 8 2.divided by 8 gives remainder 7 3.divided by 7 gives remainder 6 4.divided by 6 gives remainder 5 and so on till it is divided by 2 and remaider 1?

Answer 1

Remove the common factors.

6 = 3 x 2...as 3 is contained within the number 9 and 2 is contained within the number 8 then 6 is discarded.

4 is contained within the number 8 and is discarded

2 is also contained within the number 8 and is discarded.

Take the product of the remaining numbers and subtract 1.

(9 x 8 x 7 x 5 x 3) - 1 = 2520 -1 = 2519.......is the solution.