A sequence never ends. The next number in this one is 7 .
There is no sequence for a single number.
1^2 = 13^2 = 95^2 = 25so 7^2 = 49 (missing number)9^2 = 81Following the same pattern of odd numbers squared,the next number should be 11^2 = 121, not 10^2 = 100.The (100) seems to be out of sequence according to thepattern.
The next would be 7. 100 minus 48 is 52. 52 minus 24 (half of 48) is 28. 28 minus 12 (half of 24) is 16. etc.. The next in the sequence after 7 would be 5.5.
If the sequence is determined by 100 - 70 = 30, then the next number is 10.
It is: 10-3 = 7
4 5 6 7 8
A sequence never ends. The next number in this one is 7 .
It is: 10-3 = 7
To get the number to complete the sequence, divide the first number by 2 and then plus 2 to get the next number. Given 100, 52, 28, 16, 10 ____Solution100 / 2 (+2) = 5252 / 2 (+2) = 2828 / 2 (+2) = 1616 / 2 (+2) = 1010 / 2 (+2) = 7Therefore, the number to complete the sequence is 7.
There is no sequence for a single number.
1^2 = 13^2 = 95^2 = 25so 7^2 = 49 (missing number)9^2 = 81Following the same pattern of odd numbers squared,the next number should be 11^2 = 121, not 10^2 = 100.The (100) seems to be out of sequence according to thepattern.
The next would be 7. 100 minus 48 is 52. 52 minus 24 (half of 48) is 28. 28 minus 12 (half of 24) is 16. etc.. The next in the sequence after 7 would be 5.5.
7 The pattern is to divide the number by 2, and adding 2 to the answer. 100 . 50 . 52 52 . 26 . 28 28 . 14 . 16 16 . 8 . 10 10 . 5 . 7
If the sequence is determined by 100 - 70 = 30, then the next number is 10.
The next number would be 7 * * * * * An assertion with no rationale or justification. I suggest 10, with the following rationale: fit the sequence t(n) = (n4 - 18n3 + 131n2 - 474n + 760)/4 for n = 1, 2, 3, ...
100