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4x2 - 4x plus 2xy - 2y?
4x2 - 4x + 2xy - 2y = 4x(x - 1) + 2y(x - 1) = (x - 1)(4x + 2y) = 2(x - 1)(2x + y)
What is 4xy minus 2y parenthesies x plus 4 parenthasies simplified?
4xy - 2y(x + 4) = 4xy - 2xy - 8y = 2xy - 8y = 2y(x - 4)
When you at 2x plus 2y does it equal 2xy or 4xy?
The expression (2x + 2y) does not equal (2xy) or (4xy). Instead, it represents the sum of two terms, (2x) and (2y). If you factor it, you could write it as (2(x + y)), but it does not simplify to a product of (xy).
Whats the factor from of 2xy-4x plus 8y-16?
2xy - 4x plus 8y - 16 equals x plus 4 in parentheses multiplied by 2y minus 4 in parentheses. So, the factors are ( x + 4) and ( 2y - 4) .
What is the factor for 4x squared - 4x plus 2xy -2y?
2(x - 1)(2x + y)
Is 2y or 2xty an example of a binomial?
No
Simplify 8 -x 2y you 2y - x?
8-x2y 8-2xy 2xy-8
How do you factor 4x2-4x plus 2xy-2y?
4x2 - 4x + 2xy - 2y = 4x(x - 1) + 2y(x - 1) (4x + 2y)(x - 1).
(x2 + 2y) (x3 - 2xy + y3)?
(x^2 + 2y)(x^3 - 2xy + y^3) = x^2(x^3 - 2xy + y^3) + 2y(x^3 - 2xy + y^3) Now, let's distribute each term: = x^2 * x^3 - x^2 * 2xy + x^2 * y^3 + 2y * x^3 - 2y * 2xy + 2y * y^3 Now, simplify each term: = x^5 - 2x^3y + x^2y^3 + 2x^3y - 4xy^2 + 2y^4 Now, combine like terms: = x^5 + x^2y^3 - 4xy^2 + 2y^4 So, the expanded form of (x^2 + 2y)(x^3 - 2xy + y^3) is x^5 + x^2y^3 - 4xy^2 + 2y^4.
4x2 - 4x plus 2xy - 2y?
4x2 - 4x + 2xy - 2y = 4x(x - 1) + 2y(x - 1) = (x - 1)(4x + 2y) = 2(x - 1)(2x + y)
What is 4xy minus 2y parenthesies x plus 4 parenthasies simplified?
4xy - 2y(x + 4) = 4xy - 2xy - 8y = 2xy - 8y = 2y(x - 4)
Is 2y a binomial?
No.
How do you factor 6x4y5-4x3y3 2x2y2?
2x^2y^2(3x^2y^3 - 2xy + 1)
Solve for y if the equation is -2x - 2y equals -12?
-2x - 2y = -122x + 2y = 122y = 12 - 2xy = 6 - x
Whats the factor from of 2xy-4x plus 8y-16?
2xy - 4x plus 8y - 16 equals x plus 4 in parentheses multiplied by 2y minus 4 in parentheses. So, the factors are ( x + 4) and ( 2y - 4) .
-2xy 3x plus 2y distribute?
There are not enough terms to distribute in any meaningful way.
How do you factor the binomial x to the third y-4xy to the third?
xy(x - 2y)(x + 2y)
