A point lies on a line if the coordinates of the point satisfy the equation of the line.
The point lies 1 unit below the regression line.
To determine if a point is on a line, you can use the equation of the line. For example, if the line is represented by the equation (y = mx + b) (slope-intercept form), substitute the x-coordinate of the point into the equation to see if the resulting y-value matches the point's y-coordinate. If they match, the point lies on the line; if not, it does not. Alternatively, you can use other forms of the line equation, such as standard form, to perform a similar check.
To determine if the point S (2, -3) lies on the line represented by the equation (x - 2y - 4 = 0), we substitute the coordinates into the equation. Substituting (x = 2) and (y = -3): (2 - 2(-3) - 4 = 2 + 6 - 4 = 4), which is not equal to 0. Therefore, the point S (2, -3) does not lie on the line.
A point - unless the line lies within the plane, or is parallel to it.
A point lies on a line if the coordinates of the point satisfy the equation of the line.
Assuming the line is 3x - 2y = 4, the point (1, -1/2) lies in it.
ray
The point lies 1 unit below the regression line.
To determine if a point is on a line, you can use the equation of the line. For example, if the line is represented by the equation (y = mx + b) (slope-intercept form), substitute the x-coordinate of the point into the equation to see if the resulting y-value matches the point's y-coordinate. If they match, the point lies on the line; if not, it does not. Alternatively, you can use other forms of the line equation, such as standard form, to perform a similar check.
To determine if the point S (2, -3) lies on the line represented by the equation (x - 2y - 4 = 0), we substitute the coordinates into the equation. Substituting (x = 2) and (y = -3): (2 - 2(-3) - 4 = 2 + 6 - 4 = 4), which is not equal to 0. Therefore, the point S (2, -3) does not lie on the line.
It is the real number whose length represents the distance from the zero on the line to the point on the line.
A point - unless the line lies within the plane, or is parallel to it.
It lies in middle of the DC load line of that Amplifier.
To determine if the point (23) lies on the line given by the equation ( x - 2y - 4 = 0 ), we need to substitute the coordinates of the point into the equation. Since (23) is not a complete coordinate point (it lacks a y-value), we cannot evaluate it against the line's equation. If a full coordinate point (like (23, y)) is provided, we could check if it satisfies the equation.
upon itself
A number of point lies on it...................(-2,-44), (-1,-19),(0,6), (1,31), (2, 56)...............