Wiki User
∙ 12y agoC
4 carbons is where you get the "but" (butane). the three "C's" next to each other (in answer C) tells me that it has a triple bond, which is the Alkyne functional group. Alkyne's end with "-yne".
At least that's what I think, hopefully someone smart will come along and properly explain it, I'm just now learning it and so to my limited knowledge, I do believe it's C.
Wiki User
∙ 12y agoButhane is a saturated hydrocarbon. That means all the bonds found in this molecule are single covalent bond. Its formula is C4H10. It is the fourth member of the alkane siri.
There 4 isomers : 1) H2C=CHCH2CH3 => but-1-ene 2) CH3CH=CHCH3 => but-2-ene 3) (CH3)2C=CHCH3 => 2- methylpropene 4) CH2-CH2-CH2-CH2 => cyclobutane/cycloalkane. C4h8 has 3 isomers from the same homologous series and one that is not from the same homologous series.
There are at least 5 CH3OCH2CH2CH2CH2CH3 methoxy pentane CH3CH2OCH2CH2CH2CH3 ethoxy butane CH3CH2CH2OCH2CH2CH3 propoxy propane CH3CH(CH3)O(CH3)CHCH3 diisopropyl ether CH3CH2CH2O(CH3)CHCH3 propyl isopropyl ether + CH3OCH2CH2CH2CH2CH3 methoxy pentane with isomers of the pentane chain CH3CH2OCH2CH2CH2CH3 ethoxy butane with isomers of the butane chain
The correct name for CH3CH2HC=CHCH3 is 2-butene.
Lancelord Kgomokhumo The answer is HYDROCHLORIC ACID.
Pentene (CH3CH2CH=CHCH3) reacts with bromine by undergoing an addition reaction. The equation would be: CH3CH2CH=CHCH3 + Br2 --> CH3CH2CHBrCHBrCH3
It is a hydrocarbon with the formula, C4H10
The formula looks like trans- 2-butene. The c atoms working left to right will have sp3 sp2 sp2, sp3 hybridisation. the bond angles will be tetrahedral on the sp3 centers, 120 0 on the sp2 centres which have a planar shape, with all four substituents lying in the same plane. Good picture in wikipedia. The actual bond angles will deviate slightly.
The condensed structural formula for 1-pentene is CH3CH2CH=CHCH3.
1-dehydrohalogenation of n-propylbromide which gives the propene. CH3-CH2-CH2-Br + KOH(Alcoholic) -----> CH3-CH=CH2 2-again hydrohalogenation with HBr gives mostly iso-propylbromide,(Markonikov's rule). CH3-CH=CH2 + HBr ------> CH3-CHBr-CH3 3-The reaction of iso-propylbromide with Sodium metal in presence of anhydrous ether (Wurtz reaction) gives the 2,3-dimethylbutane. 2(CH3-CHBr-CH3) + 2Na ---anhydrous ether--->CH3-CHCH3-CHCH3-CH3
It tell you that is contains 4 carbons (from the "-but" prefix) and it has 1 double bond (from the "ene") and that this double bond is located at the #2 carbon (from the 2). So, it looks like this:CH3CH=CHCH3
There are two covalent bonds between the two carbon atoms in butadiene. The structure of butadiene consists of a conjugated system of double bonds, with one double bond between the two carbon atoms and another double bond between the adjacent carbon atoms.