Q: Which type of lines are these x-3y equals -3?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

Perpendiculat straight lines.

3x - 2y = -2 and 6x - 4y = 0Solving both equations for y, we havey = (3/2)x + 1 and y = (3/2)xSince both lines have the same slope, they are parallel lines.

The locus of points equidistant from lines y = 0 and x = 3 is the line y = -x + 3.

They are perpendicular lines because the slopes are 3/4 and -4/3 respectively.

6

Related questions

parallel

Perpendiculat straight lines.

perpendicular

3x - 2y = -2 and 6x - 4y = 0Solving both equations for y, we havey = (3/2)x + 1 and y = (3/2)xSince both lines have the same slope, they are parallel lines.

The locus of points equidistant from lines y = 0 and x = 3 is the line y = -x + 3.

They are perpendicular lines because the slopes are 3/4 and -4/3 respectively.

6

If the second equation is: y minus 2x equals 3, then:y - 2x = 3 ⇒ y = 2x + 3 and it is parallel to y = 2x.Otherwise (with with missing operator as "plus", "multiply" or "divide"), the lines are neither parallel nor perpendicular.

They are intersecting lines.

The lines intersect at (3, 5)

That depends on the other equation which has not been given but if 2x-3y = 2 then y = 2/3x-2/3

x^3y = 2, y = 4 Substitute 4 for y: (x^3)(4) = 2 x^3 = 8 x = 2