Well, I guess you have a choice of two operations,
whichever one is easier for you.
-- Leave the decimal point where it is, and move
each and every number one place to the left.
or
-- Leave all the numbers where they are, and move
the decimal point one place to the right.
How to remember it:
When you 'times' a number, you have to get a bigger number than you started with.
If it comes out smaller, then you moved things the wrong way.
0.10 = 1/10 so that multiplying by 0.10 is the same as dividing by 10.
the answer is 4.765 10% is the same as saying 1/10. a quick way to do this is to move the decmal left by one digit. if you took 1% or 1/100 of a number then you move the decmal over 2 digits. if you took .1% or 1/1000 of a number then you move the decmal over 3 digits. this pattern continues a long as you want. it also works the other way. if you times a numeber by 10, you move the decmal right one digit, if you times a number by 100 then you move the decmal over two spaces and so on.
To find three numbers that multiply together to get 5000, one possible combination is 10, 10, and 50, since (10 \times 10 \times 50 = 5000). Another combination could be 5, 10, and 100, as (5 \times 10 \times 100 = 5000). There are multiple sets of numbers that can fulfill this condition, depending on the factors chosen.
17.8
14 times 10
0.10 = 1/10 so that multiplying by 0.10 is the same as dividing by 10.
One numbers 3 times another number.the difference between the numbers 10. Find the numbers.
Start Do 10 times read number if number > highest-number move number to highest-number end DO Print higest-number. end
9 times 10 times 10 (9x10=90x10=900)
0.4*10=4. The simply way to multiply any number by 10 is to move the decimal one place to the right. If you do that with 0.4 you'll get your answer of 4.
the answer is 4.765 10% is the same as saying 1/10. a quick way to do this is to move the decmal left by one digit. if you took 1% or 1/100 of a number then you move the decmal over 2 digits. if you took .1% or 1/1000 of a number then you move the decmal over 3 digits. this pattern continues a long as you want. it also works the other way. if you times a numeber by 10, you move the decmal right one digit, if you times a number by 100 then you move the decmal over two spaces and so on.
a different way to right numbers for example 245 in expanded form is (2 times 100) plus (4 times 10) plus (5 times 1)
To find three numbers that multiply together to get 5000, one possible combination is 10, 10, and 50, since (10 \times 10 \times 50 = 5000). Another combination could be 5, 10, and 100, as (5 \times 10 \times 100 = 5000). There are multiple sets of numbers that can fulfill this condition, depending on the factors chosen.
17.8
2 times 5 equals 10!
One way is: 10 + 10 + 10 + 10 = 40
It brings 10 pp back to one move that your pokemon knows