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Use a convenient variable, such as "x", for her age. Then, 3 years ago her age was x-3, in three years, her age will be x+3. Write an equation with this data:x = 3(x+3) - 3(x-3)And solve it:x = 3x + 9 - 3x + 9x = 18Use a convenient variable, such as "x", for her age. Then, 3 years ago her age was x-3, in three years, her age will be x+3. Write an equation with this data:x = 3(x+3) - 3(x-3)And solve it:x = 3x + 9 - 3x + 9x = 18Use a convenient variable, such as "x", for her age. Then, 3 years ago her age was x-3, in three years, her age will be x+3. Write an equation with this data:x = 3(x+3) - 3(x-3)And solve it:x = 3x + 9 - 3x + 9x = 18Use a convenient variable, such as "x", for her age. Then, 3 years ago her age was x-3, in three years, her age will be x+3. Write an equation with this data:x = 3(x+3) - 3(x-3)And solve it:x = 3x + 9 - 3x + 9x = 18
This is a riddle where the answer revolves around the status of being a father or a son. There are only 3 cars, and each person gets one, so there can only be 3 people. Thus one of the fathers must also be one of the sons. This can be achieved by having the 3 people as grandfather, father, and son. That means there are two sons, and two fathers, but only 3 people.
3 times D divided by 4 minus 3=y, where D stands for age of Dad and y stands for your age, or [3D/4]-3=y
f = s + 30, f/5 + s/3 = 14 or 3f + 5s = 210 3 x (s + 30) + 5s = 210 ie 3s + 90 +5s = 210 ie 8s = 120 so s = 15 Check: Father 45, son 15, 45/5 = 9, 15/3 = 5, 9 + 5 = 14 QED