If an event has only two possible outcomes (will happen or it wont, like in heads/tails of a coin toss) then the probability of either even is 50%
Blaise Pascal and Pierre de Fermat discovered almost all of probability , maybe one of them said it....
21 is a number. You cannot write that as a probability since it is not an event.
A probability value must always fall within the range of 0 to 1, where 0 represents an impossible event and 1 represents a certain event. Since 1.21 exceeds this range, it is not a valid probability and cannot represent the likelihood of any event occurring. Probabilities greater than 1 do not have a meaningful interpretation in the context of probability theory.
Since each event is independent, the probability remains at 0.5.
It was quite likely to be a prehistoric event since all events are dichotomous: either they happen or they don't happen. Either the sabre tooth will kill me or it won't, either I will find enough prey or I won't. There is no other outcome. So, in each case, the pair of events are mutually complementary.
Since there are 6 sides to the die, the probability of rolling a 5 on one roll is 1/6. Since each roll is an independent event the probability of the multiple results is the product of the probability of each result. So 2 consecutive 5's would occur with a probability of (1/6)(1/6) = 1/36
The probability is 0 since it did not happen.The probability is 0 since it did not happen.The probability is 0 since it did not happen.The probability is 0 since it did not happen.
Two events are equally unlikely if the probability that they do not happen is the same for each event. And, since the probability of an event happening and not happening must add to 1, equally unlikely events are also equally likely,
When dealing with probability there is a range of values of the probability of an event. The probability of an event (E) is any number (fraction or decimal) between zero and one. (0≤ P(E)≤1)When an event is certain to occur the probability of E is 1. This means that there is 100% that something will happen. This is why your sum of all the probabilities must add up to equal 1.For example: Flip a coin. You have a 50% chance of it landing on heads and a 50% chance of it landing on tails since there are only two possibilities.Let H=headsLet T=tails∑P= P(H)+P(T)=0.5+0.5=1This is telling you, you have a 100% chance of it landing on either heads or tails.If the event cannot happen the event contains no members in the sample space so its probability is zero.For example: Roll a single die one time. Find the probability of rolling a 7:This cannot happen so the probability is zero.
21 is a number. You cannot write that as a probability since it is not an event.
NO!!! In probability P(0) = Event will NOT happen/occur P(1) - Event is certain to occur. Probability answers less than zero, or greater than '1' are incorrect.
P(a^~a)==1 P(a&~a)==0 the line above is shorthand notation for an event that has a probability of 1, followed by an event that has a probability of 0. P(event) is an easy way to say the probability of "event". The "^" means "OR", the "~" means "NOT", and the "&" as you are probably familiar means "AND". So puting it together, "P(a^~a)" means the probability that an event "a" occurs OR that event "a" does not occur. So take an event "a", any event, like drawing an 8 of clubs out of a deck of cards. If you draw a random card out of a deck of cards, the probability that you will draw an 8 of clubs OR that you will not draw an 8 of clubs is 1. That means 100%. So when you draw a card you will either draw the 8 of clubs or not draw the 8 of clubs. It seems like an obvious statement to make but its a proof that becomes very important in proving less obvious theories. likewise, the second statement was "P(a&~a)", so the probability that event "a" occurs AND event "a" doesnt occur. Since the event has to either occur or not, it cant occur AND not occur, so the probability is 0.
Nothing since it is impossible. No event can have 5 as the probability of success.
Since the word "probability" contains only letters, then the probability of choosing a letter from the word "probability" is 1, i.e. it is certain to happen.
Probability = 10 is a very serious mistake since the probability of any event can never be greater than 1: so a probability of 10 is obviously a big error.
Since it is a certainty that a coin must land on either heads or tails, the probability must be 1.
The answer is that you have made a very serious mistake since the probability of any event can never be greater than 1: so a probability of 2 is obviously a big error.
Let me denote -A as the event that A does not happen. So we want Pr[-(A and B)] Now, the event that neither A nor B occurs is the opposite of either A occurring, or B occurring or both occurring. So Pr[-(A and B)] = 1 - Pr(A or B)= 1 - [Pr(A) + Pr(B) - Pr(A and B)] (since A+B is double counted)= 1 - (0.5 + 0.7 - 0.4)= 1 - 0.8= 0.2