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What date is the Shiprock fair this year 2010?
the first an sec of oct
How do you prove that the derivative of sec x is equal to sec x tan x?
Show that sec'x = d/dx (sec x) = sec x tan x. First, take note that sec x = 1/cos x; d sin x = cos x dx; d cos x = -sin x dx; and d log u = du/u. From the last, we have du = u d log u. Then, letting u = sec x, we have, d sec x = sec x d log sec x; and d log sec x = d log ( 1 / cos x ) = -d log cos x = d ( -cos x ) / cos x = sin x dx / cos x = tan x dx. Thence, d sec x = sec x tan x dx, and sec' x = sec x tan x, which is what we set out to show.
How long does it take to travel 205 feet at 6 mph?
First change mi/hr into ft/sec. There 1 mi = 5280 ft and 1 hour = 3600 sec. 6 mi/hr = 6 * (5280 ft / 3600 sec) = 8.8 ft / sec To figure out how fast you travel any distance you divide the distance by time it took you. distance / time = speed 205 ft / time = 8.8 ft / sec Solving for time: time = 205 ft / (8.8 ft / sec) time = 23 sec
What is the second derivitive of sec x?
Write sec x as a function of sines and cosines (in this case, sec x = 1 / cos x). Then use the division formula to take the first derivative. Take the derivative of the first derivative to get the second derivative. Reminder: the derivative of sin x is cos x; the derivative of cos x is - sin x.
Who was the first prime minister to live at 10 downing street?
Sir Robert Walpole, the first Prime Minister, at that time First Lord of the Treasury, of the UK.
