Because of the formula: (n-2)*180 = total sum of interior angles where n is the number of sides of the polygon.
Triangles, rectangles and octagons are all examples of a polygon. A polygon is a polygon whose sides are the same length and whose interior angles are the same measure
there r 800 vetices in three triangles
Any n-sided polygon (n being any integer) will always have a minimum of n-2 triangles inside the shape, assuming that the polygon is regular with no reflex angles.
Not that I know of, an octagon has eight sides and eight angles. Triangles have three of each, as well as hexagons. Based on that information, I'm pretty sure it's the same case with any polygon.
If a regular polygon has n sides, then the number of triangles in that polygon is n - 2. thus, the sum of its interior angles is equal to (n - 2)180°.
Because of the formula: (n-2)*180 = total sum of interior angles where n is the number of sides of the polygon.
20 triangles will fit into a 22 sided polygon whose interior angles add up to 3600 degrees
Triangles, rectangles and octagons are all examples of a polygon. A polygon is a polygon whose sides are the same length and whose interior angles are the same measure
there r 800 vetices in three triangles
Any n-sided polygon (n being any integer) will always have a minimum of n-2 triangles inside the shape, assuming that the polygon is regular with no reflex angles.
This has to do with the way in which the sum of the angles is derived. First you select a point inside the polygon and then join that point to each of the vertices. For a polygon with n sides, this gives rise to n triangles. The sum of the 3 angles of any triangle is 180 degrees. So the sum of the angles of all the triangles is n*180 degrees. Now, the "outer" angles of these triangles correspond to the interior angles of the polygon. But the sum also includes the angles formed arounf the central point. The sum of all the angles around this central point is 360 degrees. This is not part of the sum of the interior angles of the polygon and so must be subtracted. Thus, the interior angles of a polygon sum to n*180 - 360 degrees or 180*(n- 2) degrees.
By drawing all the diagonals from one vertex, the polygon is divided up into triangles. The sum of the interior angles of the polygon is equal to the sum of the internal angles in the triangles. With n vertices, each vertex is not directly connected to n-3 other vertices, thus n-3 diagonals can be drawn from a vertex which will create n-2 triangles (each with the sum of their interior angles as 180o); so: sum_of_interior_angles = 180 x (number_of_sides - 2)
540 degrees. you figure it out by seeing how many triangles you can make in the polygon (without crossing lines), and, because triangles equal 180 degrees, you multiply 180 times how many triangles you can make.
Because the exterior angles of any polygon always add up to 360 degrees
Not that I know of, an octagon has eight sides and eight angles. Triangles have three of each, as well as hexagons. Based on that information, I'm pretty sure it's the same case with any polygon.
The central angles are the angles of the apexes of the isosceles triangles with the base edges as edges of the polygon and so the central angles make a revolution about the centre of the shape. They will all add to 360. 360/36=10 The polygon with 10 sides is called the decagon.