Because that problem is essentially 2-2=0 because subtraction is just adding a negative.
And because if you have two and then take two away obviously means that you have none, adding a -2 to a positive 2 equals 0.
0+0+2=2 2 divided by 3 = 2/3
31
The equation that is quadratic in form is (6x^4 + 7x^2 - 3 = 0). This can be rewritten by letting (y = x^2), transforming it into a quadratic equation: (6y^2 + 7y - 3 = 0). The other equations do not fit the quadratic form.
The restricted value in the domain is x=-2 because if x were equal to -2, the denominator would be 0 and the expression would become undefined.
To solve this equation, you first add all the 2s together to get 14 (2+2+2+2+2+2+2=14). Then, you subtract 14 from 14, which equals 0. Therefore, the final answer is 0.
The sum of 2 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 plus 0 equals 2.
The answer is 0 because at the end it is multiplied by 0
It equals 7
0+0+2=2 2 divided by 3 = 2/3
It equals 6
31
100101 1 times 2^0 = 1 PLUS 0 times 2^1 = 0 PLUS 1 times 2^2 = 4 PLUS 0 times 2^3 = 0 PLUS 0 times 2^4 = 0 PLUS 1 times 2^5 = 32 EQUALS 37
Yes.-2 + -2 becomes -2 - 2 which is -4.-2 - -2 become -2 + 2 which is 0.
I come up with 20.
0
The restricted value in the domain is x=-2 because if x were equal to -2, the denominator would be 0 and the expression would become undefined.
To solve this equation, you first add all the 2s together to get 14 (2+2+2+2+2+2+2=14). Then, you subtract 14 from 14, which equals 0. Therefore, the final answer is 0.