In calculating minimum circuit ampacity, the factor of 1.25 is commonly applied to account for continuous loads. This multiplier ensures that the circuit can handle the load without overheating, providing a safety margin by increasing the ampacity rating. By using 1.25, the calculation considers potential variations in load and allows for the safe operation of electrical equipment over extended periods. This practice aligns with the National Electrical Code (NEC) guidelines to promote safety and reliability in electrical installations.
The easiest way to input a fraction while calculating is to simply divide the top of the fraction by the bottom. So four fifths would be (4/5). To convert an answer into a fraction, such as .125, press the math button and select >Frac. .125>frac = (1/8)
20 percent off 125 = 10020% off of 125= 20% discount applied to 125= 125 - (20% * 125)= 125 - (0.20 * 125)= 125 - 25= 100
125 x 125 = 15625
The GCF is 125.
1*125=125 or 5*25=125
The maximum current rating for the circuit breaker required for a 125 amp load is 125 amps.
Yes, no problem at all going to a larger ampacity of wire. Larger size wire yes, smaller size wire no.
If you know the size of the load to be served, multiply it by 125% ( times 1.25) and choose a conductor that is rated for that ampacity or higher.
The recommended wire size for a 125 amp electrical circuit is typically 2/0 AWG copper wire.
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For a 125 amp circuit using THHN wire, the appropriate wire size would be 1/0 AWG.
Power Factor is one of most significant parameter in calculating AC Power. As we know it is cosine of angle between AC Voltage and Current it comes in picture while calculating power in AC circuits Power In AC (P) = Voltage (V) X Current (V) X Power Factor Let us take an example of Power with Power factor and without power factor for same circuit. Let Us assume V = 125 Volts I = 1 Amp Power Factor = 1 Then P = 125X1X1= 125 Watts But for any circuit when Power factor is below 1, to execute same power, Circuit has to draw more current. for example P = 125X 1.25 X 0.8 = 125 Watts In first example power factor of the circuit was unity = 1 and in that condition current of the circuit was 1 amp whereas in second example power factor of the circuit is 0.8 due to which current of the circuit increases to 1.25 amp to execute the same power. Now due to increase in current of the circuit many factors are affected like heat loss, Conductor's specification , Class of insulation etc. Thus it can be concluded after going through above explanation that power factor play a significant role in AC power calculation as well as in actual practices.
The electrical code states that motor feeders have to be rated at 125% of the FLA of the motor. When wiring motor circuits always consider the ambient temperature (for wire de-rate purposes) where the motor is located and the 125% rule before selecting the correct wire size. <<>> Extra care must be taken when calculating power requirements for circuits that will carry electric motors because the current need of an electric motor is larger than calculated from its horsepower rating alone. Electric motors are highly inductive and also have an in-rush current requirement to get started. The circuit used to power an electric motor has to be capable of supplying the in-rush and steady state currents to the motor -- with an acceptable I^2-R loss on the wires.
It is 125*8 = 1000
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