Explain why the numbers 1 2 3 4 5 6 7 8 9 10 11 can't be arranged into a prime sum circle.
2 * (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11) = 132, an even sum.
since smallest prime applicable in "prime sum" is 3 (and not 2, the only even prime), with 11 boxes in between to house an ODD prime each, but sum of 11 odds = odd =/ 132.
hnmhv
what prime numbers have the sum of 54
Sum of what?
the prime factors of sum of 121 is 112 and 22
sum of the 13th and 14th and 15th prime numbers = 1311st to 12 prime numbers = 2, 3,5,7,11,13,17,19,23,29,31,3713th prime number = 4114th prime number = 4315th prime number = 47=================sum.......................=131
hnmhv
what prime numbers have the sum of 54
16prime + prime = (sum) sum is 16or13 + 3 =16
Sum of what?
The sum of the first 25 prime numbers is 1,060.
which three prime numbers have a sum of 59
the prime factors of sum of 121 is 112 and 22
The sum of the first two prime numbers is 5.
It isn't possible.
There are not three prime numbers that have the sum of 3. The smallest prime number is 2. If all three prime numbers were 2, the sum would 2 + 2 + 2 = 6, so that is the smallest number that is the sum of three prime numbers.
The sum of two prime numbers will be composite unless one of the prime numbers is 2.
The sum of any two prime numbers may or may not be prime. The sum of the two prime numbers 2 and 3 is the prime number 5, and the sum of the two prime numbers 5 and 7 is the composite number 12.